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liraira [26]
3 years ago
12

The temperature of a superconductor is gradually lowered. At the critical temperature, how does the resistivity of the supercond

uctor change?
A. It reaches a constant positive value
B. It suddenly drops to zero
C. It begins a gradual decrease
D. It experiences a spike to its highest value
Physics
1 answer:
san4es73 [151]3 years ago
8 0

At critical temperature, the resistivity of the superconductor

B. It suddenly drops to zero

Explanation:

Materials can be classified into three different types depending on their resistance:

  • Conductors: these materials have generally low resistance and allow electricity to pass through easily. The resistance of a conductor increases linearly with the temperature
  • Insulators: these materials do not allow electricity to pass through - so they have very high resistance
  • Semi-conductors: these are materials that are insulators are room temperature, however they becomes conductors when heated. Therefore, the resistance of a semiconductor decreases when the temperature increases
  • Superconductors: these are special materials that are normally conductors; however, at very low temperatures (we are talking about temperature very near to 0 K), their resistance becomes suddenly zero.

Therefore, the correct answer is:

B. It suddenly drops to zero

Learn more about current and resistance:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

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hydorgen bond

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A pillow with mass of 0.3 kg sits on a bed with a coefficient of static friction of 0.6. What is the maximum force of static fri
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The maximum force of static friction is the product of normal force (P) and the coefficient of static friction (c). In a flat surface, normal force is equal to the weight (W) of the body. 
 
                        P = W = mass x acceleration due to gravity
    
                    P = (0.3 kg) x (9.8 m/s²) = 2.94 kg m/s² = 2.94 N

Solving for the static friction force (F), 
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2 years ago
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A person travels by car from one city to another with differem constan1 speeds between pairs of cities. She drives for 30.0 min
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Answer:

a.52.9 km/h

b.90 km

Explanation:

We are given that

v_1=89km/h

t_1=30min

v_2=100km/h

t_2=12min

v_3=40km/h

t_3=45 min

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Distance=speed\times time

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Average speed=\frac{total\;speed}{total\;time}

Using the formula

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3 years ago
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Answer:

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