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sergij07 [2.7K]
3 years ago
7

A mechanic has a wrench where the hand grip is 0.40 m from the axis of the bolt. To apply a torque of 170 N m with this wrench w

hile pushing at right angles to the wrench, the mechanic must exert a force of a. 0.0024 N b. 68. N c. 1.7 x 10 N d. 4.3 x 10 N e. None of these
Physics
1 answer:
Grace [21]3 years ago
4 0

Answer:

4.3 * 10 N

Explanation:

To calculate torque, we multiply the distance from the pivot by the perpendicular (the part of the force that acts at right angles to the displacement vector) component of the force to the displacement vector from the pivot.

torque  = distance from pivot *  perpendicular force

170 Nm= 0.4 m * F

F = 425 N = 4.3 * 10 N rounded off to two significant figures

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Which two phrases describe a situation that will cause an object moving at a
notsponge [240]

Answer:

The phrases the describe the situation are A and C

Explanation:

1- If a car is at rest or uniform motion, it will remain in that condition until an external force acts on it. If the external forces acting on a body are balanced , it means that their sum is equals to 0, which eventually results that no Net force is acting on it.

For balance forces, ∑F = 0

2- If the car moving at a constant speed is slowing down, it means that the forces have become unbalanced, eventually resulting in a Net force in the opposite direction of the motion of the car, due to which it is slowing down

For unbalanced forces, ∑F ≠ 0

The question satisfies 2, which is the answer

4 0
3 years ago
Charlie pulls horizontally to the right on a wagon with a force of 37.2 N. Sara pulls horizontally to the left with a force of 2
Sidana [21]

Answer:

The work done on the wagon is 37 joules.

Explanation:

Given that,

The force applied by Charlie to the right, F = 37.2 N

The force applied by Sara to the left, F' = 22.4 N

We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :

F_n=F-F'

F_n=37.2-22.4

F_n=14.8\ N

Work done on the wagon is given by the product of net force and displacement. It is given by :

W=F_n\times d

W=14.8\ N\times 2.5\ m

W = 37 Joules

So, the work done on the wagon is 37 joules. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
A gun is fired with angle of elevation 30°. What is the muzzle speed if the maximum height of the shell is 544 m? (Round your an
Artemon [7]

Answer:

206.62313 m/s

Explanation:

u = Muzzle speed

g = Acceleration due to gravity = 9.8 m/s²

\theta = Angle at which the bullet is fired = 30°

h = Maximum height = 544 m

Maximum height is given by

h=\dfrac{u^2sin^2\theta}{2g}\\\Rightarrow u=\sqrt{\dfrac{2gh}{sin^2\theta}}\\\Rightarrow u=\sqrt{\dfrac{2\times 9.81\times 544}{sin^2(30)}}\\\Rightarrow u=206.62313\ m/s

The muzzle speed is 206.62313 m/s

6 0
4 years ago
A man drops a baseball off of the top of the Empire State Building. If the action force is the Earth pulling on the ball, then w
stepladder [879]
Reaction force is the ball pulling up on the Earth. Every action has an equal and opposite reaction, so when the Earth pulls on the baseball, the baseball pulls back on the Earth with equal force
7 0
3 years ago
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A 5 kilogram cat is resting on top of a bookshelf that is 3 meters high. What is the cat’s gravitational potential energy relati
Free_Kalibri [48]
U=mgh
U=5kg*9.8N/kg*3m
U=147J
5 0
3 years ago
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