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2 years ago

Im bored please talk to me

Mathematics

2 answers:

Sunny_sXe [5.5K]2 years ago

6 0

Answer:

Step-by-step explanation:

Nice to meet you uwu XD Lol

tankabanditka [31]2 years ago

3 0

Answer:

I am sorry you are bored

Step-by-step explanation:

You might be interested in

This is a question on my partial fractions homework, but no matter what I try I can't figure it out..

Ierofanga [76]

$\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}$
$\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}$
$\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)$
$\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3$

So you have

$\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$
$=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$

where in the first integral we substitute $x\mapsto x+1$ .

$=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}$
$=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)$
$=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2$
$=\dfrac23+\ln\dfrac89$

4 0

3 years ago

What is 5.823 rounded to the nearest whole<br> what is 3.147 rounded to the nearest whole

stich3 [128]

Answer:

6 and 3

Step-by-step explanation:

5.8 to the nearest whole is 6

3.147 to the nearest whole is 3

7 0

2 years ago

Plz, HELP me with this question!

vodomira [7]

Answer:

Experimental property.

Step-by-step explanation:

I say this because the experimental probability is the actual result of an experiment, which may be different from theoretical probability. Theoretical probability is determined by thinking, and what you think the outcome will be.

7 0

3 years ago

Read 2 more answers

Juan had $24400 and chose to split the money into two different mutual funds. During the first year, Fund A earned 4% interest a

Sidana [21]

Answer: Juan invested $14,900 in Fund A and $9,500 in Fund B.

Step-by-step explanation:

Let x= Amount invested in Fund A .

Since , total amount invested = $24400

Then, Amount invested in Fund B = 24400-x

Fund A earned 4% interest and Fund B earned 6% interest.

Interest earned by Fund A= 4% of x = 0.04 x

Interest earned by Fund B= 6% of x = 0.06 ( 24400-x)

= 0.06(24400)-0.06x

= 1464-0.06x

Total interest = 0.04x+1464-0.06x= 1464-0.02x

If he received a total of $1166 in interest, then

$1464-0.02x =1166\\\\\Rightarrow\ 0.02x=1464-1166\\\\\Rightarrow\ 0.02x=298\\\\\Rightarrow\ x=\dfrac{298}{0.02}=14900$

So, Amount invested in Fund A = $14900

Amount invested in Fund B = $( 24400-14900 ) = $9500

Hence, Juan invested $14,900 in Fund A and $9,500 in Fund B.

5 0

2 years ago

10 inches equals how many millimeters?

solong [7]

1 in equals 25.4 mm

so in this case you multiply 25.4 times 10

to get 254

4 0

3 years ago

Read 2 more answers