Why are being flammable and combustible considered to be chemical properties and not physical properties?

Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. The balanced chemical equation

Rufina [12.5K]

The mass formed in a chemical reaction is given by stoichiometry law in balanced chemical equation. The mass of silver produced in the reaction is 107. 9 g.

<h3>What is the stoichiometric law?</h3>

The stoichiometric law states that in a balanced chemical equation, the stoichiometric coefficient describes the moles of each compound in a chemical reaction.

The balanced chemical equation for the reaction is:

$\rm Cu\;+\;2\;AgNO_3\;\rightarrow\;Cu(NO_3)_2\;+\;2\;Ag$

From the balanced chemical equation, 1 moles of copper results in 2 moles of silver.

Moles in terms of mass can be given as:

$\rm Moles=\dfrac{Mass}{Molar\;mass}$

Thus, moles of 31. 75 grams copper is:

$\rm Cu=\dfrac{ 31. 75 }{63.5}\;mol\\ Cu=0.5 mol$

The moles of Ag produced can be given from stoichiometric law as:

$\rm 1\;mol\;Cu=2\;mol\;Ag\\0.5 \;mol\;Cu=0.5\;\times\;2\;mol\;Ag\\0.5\;mol\;Cu=1\;mol\;Ag$

The moles of Ag produced is 1 mol.

The mass of a mole of element is equivalent to the molar mass. Thus, the mass of Ag produced in the reaction is 107. 9 g. Hence, option B is correct.

Learn more about stoichiometric law, here:

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7 0

2 years ago

How do we balance a chemical equation?

Papessa [141]

Answer: placing coefficients

Explanation: In a balanced chemical equation, the total number of atoms of each element present is the same on both sides of the equation. Stoichiometric coefficients are the coefficients required to balance a chemical equation. These are important because they relate the amounts of reactants used and products formed.

3 0

2 years ago

Substance _____ involves repeated, harmful use of a substance whereas substance _____ is a physical and/or psychological addicti

alina1380 [7]

Substance abuse... Substance addiction or dependence??

6 0

3 years ago

How many grams of CO2 will be produced when 8.50 g of methane react with 15.9 g of O2, according to the following reaction? CH4(

Vedmedyk [2.9K]

Taking into account the reaction stoichiometry, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CH₄ + 2 O₂ → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CH₄: 1 mole
O₂: 2 moles
CO₂: 1 mole
H₂O: 2 moles

The molar mass of the compounds is:

CH₄: 16 g/mole
O₂: 32 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CH₄: 1 mole ×16 g/mole= 16 grams
O₂: 2 moles ×32 g/mole= 64 grams
CO₂: 1 mole ×44 g/mole= 44 grams
H₂O: 2 moles ×18 g/mole=36 grams

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 16 grams of CH₄ reacts with 64 grams of O₂, 8.50 grams of CH₄ reacts with how much mass of O₂?

$mass of O_{2} =\frac{8.50 grams of CH_{4}x64 grams of O_{2} }{16grams of CH_{4}}$

mass of O₂= 34 grams

But 34 grams of O₂ are not available, 15.9 grams are available. Since you have less mass than you need to react with 8.50 grams of CH₄, O₂ will be the limiting reagent.

<h3>Mass of CO₂ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 64 grams of O₂ form 44 grams of CO₂, 15.9 grams of O₂ form how much mass of CO₂?

$mass of CO_{2} =\frac{15.9 grams of O_{2}x44 grams of CO_{2} }{64grams of O_{2}}$

<u><em>mass of CO₂= 10.93 grams</em></u>

Then, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.

Learn more about the reaction stoichiometry:

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6 0

1 year ago

What is a heterogeneous mixture?

vladimir1956 [14]

Answer:

The type of mixture whose components are seen through our naked eyes is known as heterogeneous mixture. it is a mixture of small constituent parts of substances.

for eg, mixture of sand and sugar.

<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

7 0

2 years ago