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ser-zykov [4K]
3 years ago
10

Name at least two benefits of using models in science

Chemistry
2 answers:
scoray [572]3 years ago
8 0

Answer:

Viewing systems from multiple perspectives.

Discovering causes and effects using model tractability.Explanation:

good luck:)

STatiana [176]3 years ago
3 0

Answer:

Viewing systems from multiple perspectives.

Discovering causes and effects using model tractability.

Improving system understanding through visual analysis.

Explanation:

Got this from google, lol. But, I put three here just in case you could get extra credit for more than two.

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solniwko [45]
Nothing, he shouldn’t be able to move it. Think about it like this say you try really hard to push something that is 5,000 pounds and you push as hard as you can. Well you can’t move it bc it weighs more than you can push. I’m sure their is a equation you can use to see how much you can push (body weight=force?)
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3 years ago
Complete the sentences to explain your reasoning.
tangare [24]

Answer:

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Explanation:

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Helllppppppppp Don’t Guess
ruslelena [56]

Answer:

C. Lithium

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I Goo gled it and I think that's right.

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2 years ago
Select the correct answer. Which of these elements is a transition metal?
PtichkaEL [24]

I don't see the options for an answer, so here is a list of all of the transition metals lol

  • <em>Scandium</em>
  • <em>Titanium</em>
  • <em>Vanadium</em>
  • <em>Chromium</em>
  • <em>Manganese</em>
  • <em>Iron</em>
  • <em>Cobalt</em>
  • <em>Nickel</em>
  • <em>Copper</em>
  • <em>Zinc</em>
  • <em>Yttrium</em>
  • <em>Zirconium</em>
  • <em>Niobium</em>
  • <em>Molybdenum</em>
  • <em>Technetium</em>
  • <em>Ruthenium</em>
  • <em>Rhodium</em>
  • <em>Palladium</em>
  • <em>Silver</em>
  • <em>Cadmium</em>
  • <em>Lanthanum</em>
  • <em>Hafnium</em>
  • <em>Tantalum</em>
  • <em>Tungsten</em>
  • <em>Rhenium</em>
  • <em>Osmium</em>
  • <em>Iridium</em>
  • <em>Platinum</em>
  • <em>Gold</em>
  • <em>Mercury</em>
  • <em>Actinium</em>
  • <em>Rutherfordium</em>
  • <em>Dubnium</em>
  • <em>Seaborgium</em>
  • <em>Bohrium</em>
  • <em>Hassium</em>
  • <em>Meitnerium</em>
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8 0
2 years ago
What is the molarity of a stock solution if 60 mL were used to make 150 ml<br>of a .5M solution? ​
olga2289 [7]

The molarity of the stock solution is 1.25 M.

<u>Explanation:</u>

We have to find the molarity of the stock solution using the law of volumetric analysis as,

V1M1 = V2M2

V1 = 150 ml

M1 = 0.5 M

V2 = 60 ml

M2 = ?

The above equation can be rearranged to get M2 as,

M2 = $\frac{V1M1}{V2}

Plugin the values as,

M2 = $\frac{150 \times 0.5}{60}

       = 1.25 M

So the molarity of the stock solution is 1.25 M.

4 0
2 years ago
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