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mash [69]
3 years ago
5

Calculate the molarity of the solution.

Chemistry
2 answers:
borishaifa [10]3 years ago
6 0

Answer:

The molarity of the solution is 0.05 \frac{moles}{L}

Explanation:

Molarity (M) is the number of moles of solute that are dissolved in a given volume.

Molarity is determined by the following expression:

Molarity (M)=\frac{number of moles of solute}{dissolution volume}

Molarity is expressed in units \frac{moles}{liter}.

Then you should know the amount of moles of HCL. For that you should know that:

The Avogadro Number or Avogadro Constant is called the number of particles that constitute a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance.  Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.

Therefore, applying a rule of three, 6.02*10²² molecules correspond to:

moles=\frac{6.02*10^{22}*1mole }{6.023*10^{23} }

moles=0.1 moles of HCl

Applying the definition of molarity:

M=\frac{0.1 moles}{2 L}

M= 0.05 \frac{moles}{L}

<u><em>The molarity of the solution is 0.05 </em></u>\frac{moles}{L}<u><em></em></u>

olga nikolaevna [1]3 years ago
4 0

Answer:

ans. is 0.05

Explanation:

molarity=(mole of solute)/(litre of solution)

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In finding the molarity of a solution, we use the following formula:

M=moles soluteL solution

What is Molarity?

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<h3 />

The molar mass of  NH4NO3 and (NH4)3PO4 are  80.043 g/mol and 149.0867 g/mol, respectively.

molesNH+4inNH4NO3=5.66 g80.043 g/mol×1molNH+41molNH4NO3=0.0707 mol

molesNH+4in(NH4)3PO4=4.42 g149.0867 g/mol×3molNH+41mol(NH4)3PO4=0.0889 mol

total molesNH+4=0.0707 mol+0.0889 mol=0.1596 mol

molesPO3−4in(NH4)3PO4=4.42 g149.0867 g/mol×1molPO3−41mol(NH4)3PO4=0.0296 mol

[NH+4]=0.1596 mol20.0 L=7.98×10−3 M NH+4

[PO3−4]=0.0296 mol20.0 L=1.48×10−3 M PO3−4

Therefore, [PO3−4]\\ has a molarity of  1.48×10−3 M PO3−

To learn more about Molarity click on the link below:

brainly.com/question/19943363

#SPJ4

5 0
2 years ago
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