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ziro4ka [17]
3 years ago
9

Which of the following microscopic soil life forms is also known as a “ring worm”?

Chemistry
2 answers:
UNO [17]3 years ago
8 0
Protozoa is known as ring worm
OverLord2011 [107]3 years ago
3 0

Answer:

nematodes

Explanation:

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An endothermic dissolution process a. absorbs energy as heat and has positive enthalpy of solution. b. releases energy as heat a
Whitepunk [10]

Answer:

a. absorbs energy as heat and has positive enthalpy of solution.

Explanation:

A reaction can either be exothermic or endothermic. An endothermic reaction, as the dissolution described in the question, is that which absorbs heat energy from the surroundings in order to start the reaction.

Because an endothermic reaction makes heat lost from the surroundings, the enthalpy (∆H) of the solution will be positive (+). ∆H is got by finding the difference between the enthalpy of the reactants and products and since the enthalpy of a product in endothermic reaction is more, the enthalpy change (∆T) will be positive.

8 0
3 years ago
What changes happen to ions which are attracted to cathode during electrolysis?
saul85 [17]

Answer:

es este 167 es el te d ultado espero te ayude

6 0
3 years ago
Which of the following elements is the most reactive?<br> A. Ba<br> B. Cs<br> C. Hf<br> D. Lu
hodyreva [135]

Answer: Cs because its further to the right on the table, meaning its more reactive.

Explanation:

8 0
3 years ago
A student weighed out a 2.055 g sample of a cobalt chloride hydrate, ConClmpH2O, where n, m, and p are integer values to be dete
topjm [15]

The given mass of cobalt chloride hydrate = 2.055 g

A sample of cobalt chloride hydrate was heated to drive off waters of hydration and the anhydrate was weighed.

The mass of anhydrous cobalt chloride = 1.121 g anhydrate.

The mass of water lost during heating = 2.055 g - 1.121 g = 0.934 g

Converting mass of water of hydration present in the hydrate to moles using molar mass:

Mass of water = 0.934 g

Molar mass of water = 18.0 g/mol

Moles of water = 0.934 g * \frac{1 molH_{2}O }{18 g H_{2}O } =0.0519 mol H_{2}O

8 0
2 years ago
What<br>was the initial volume of the hydrogen in cm3?​
svetlana [45]

Answer:

255.51cm3

Explanation:

Data obtained from the question include:

V1 (initial volume) =?

T1 (initial temperature) = 50°C = 50 + 273 = 323K

T2 (final temperature) = - 5°C = - 5 + 237 = 268K

V2 (final volume) = 212cm3

Using the Charles' law equation V1/T1 = V2/T2, the initial volume of the gas can be obtained as follow:

V1/T1 = V2/T2

V1/323 = 212/268

Cross multiply to express in linear form

V1 x 268 = 323 x 212

Divide both side by 268

V1 = (323 x 212)/268

V1 = 255.51cm3

Therefore, the initial volume of the gas is 255.51cm3

5 0
3 years ago
Read 2 more answers
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