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puteri [66]
4 years ago
8

When the surface water temperature is still well below the water boiling temperature, some bubbles at the bottom tend to float u

p but somehow the bubbles seem to disappear before reaching the surface. What is the most likely scenario for these bubbles?
Chemistry
1 answer:
irga5000 [103]4 years ago
7 0

Answer:

The reasons why the seemingly floating bubbles disappear was that they tend to loss their latent heat to the water molecules at the surface water.

Explanation:

Heat energy has a considerable effect on the velocity of molecules including water. The water molecules below the container will receive much more heat energy than those above it. This heat energy in the form of specific heat capacity and latent heat that result in the increase in the speed of individual molecules of water and finally to the escape of the molecules to a colder region of the container, in this case the upper region. At the collision of the bottom water to the surface water, they tend to exchange their heat content, the hotter molecules will lose their heat to the cold ones. When the formerly hot molecules encounter this, it will result in lowering the temperature and consequentially to the reduction of their movement, once in the form of bubble, now become ordinary water. This convectional transfer of heat energy will continue until the whole system has a uniform temperature depending on the consistency of the heat source.

You might be interested in
How many moles in 68.1 grams of Cu(OH)2
Andrew [12]

To do this, you would first add together the molar mass of all involved elements, to find how many grams are in a mole of Cu(OH)2. Keep in mind, the molar mass is equal to the atomic mass of an element in grams. For example the molar mass of copper (Cu) would be 63.55 (with 2 sig. figs.)

Therefore, now we add together the mass of all elements involved.

Cu: (63.55)+O2(15.99x2=31.98)+H2(1.01x2=2.02)

63.55+31.98+2.02= 97.55g per mole of Cu(OH)2.

Now, divide what we have by how much it takes to get a mole of the stuff.

68.1/97.55= 0.698mol Cu(OH)2


6 0
3 years ago
What is the Lewis structure of CH4​
Triss [41]

Answer:

8 Toal valence electrons.

Explanation:

For CH4 you have a total of 8 total valence electrons. Drawing the Lewis structure for CH4 (named methane) requires only single bonds. It's one of the easier Lewis structures to draw.

6 0
3 years ago
Aluminium oxide has a very high melting point (2072 degrees C) while carbon dioxide has a very low boiling point (-57 degrees C)
____ [38]

Answer:

Well, Aluminum Oxide has a very high melting point. Carbon dioxide has a very low boiling point.

Explanation:

They are both talking about different things, melting and boiling. Aluminum Oxide's melting point is much higher then carbon dioxide's melting point. Hope this help, and good luck on your assignment (if one)

5 0
4 years ago
Write the following in scientific notation. a) 4,502,000 b) 450 c) 0.000458 d) 0.245
kykrilka [37]

Answer:

a 4.502 × 10 6

b 4.5 × 10 2

c 4.58 × 10 -4

d  2.45 × 10 -1

Explanation:

5 0
4 years ago
I need help on this someone please help
Murljashka [212]

1) Dawn dish soap has a density of 1.06 g/mL. If the mass of a sample of the liquid is 1.00 g what is the volume?

Answer:

v = 0.94 mL

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Given data:

Density of soap =  1.06 g/mL.

Mass  = 1 g

Volume = ?

Solution:

d = m/v

v = m/d

v = 1 g/1.06 g/mL

v = 0.94 mL

2) Maple syrup has a density of 1.37 g.mL. What is the mass of 1.0 L of the maple syrup?

Answer:

m = 1370 g

Given data:

Density of soap =  1.37 g/mL.

Mass  = ?

Volume = 1.0 L ( 1000 mL)

Formula:

D=m/v

D= density

m=mass

V=volume

Solution:

d = m/v

m = d × v

m = 1.37 g/mL  ×  1000 mL

m = 1370 g

3) The density of gasoline is 0.754 g/mL. A drop of gasoline has a mass of 22 g what is the volume?

Answer:

v = 29.2 mL

Given data:

Density of soap =  0.754 g/mL.

Mass  = 22 g

Volume = ?

Formula:

D=m/v

D= density

m=mass

V=volume

Solution:

d = m/v

v = m/d

v = 22 g/0.754 g/mL

v = 29.2 mL

6 0
3 years ago
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