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irina1246 [14]
3 years ago
14

Please help me out i'm new here but i really need help for science (if you need help with any hw like ela i can help!) (50 point

s) ima give more out in my other questions this is the 2 question make sure go to the first one!
Question 6 Slide 8 Pg 153 (image 1)
Is it...?? Choose one (check the image to see the questions and question answers)
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2.
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Question 7 Slide 8 Pg 153 * (image 1)
Is it...?? Choose one (check the image to see the questions and question answers)
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2.
3.
4.

Question 8 Slide 8 Pg 153 * (image 1)
State the independent variable in this investigation?

Question 18 Slide 11 Pg 158 (image 2)

Is it...?? Choose one (check the image to see the questions and question answers)
1.
2.
3.
4.

Question 19 Slide 11 Pg 158 (image 2)
Is it...?? Choose one (check the image to see the questions and question answers)
1.
2.
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Question 20 Slide 11 Pg 158 (image 2)

Is it...?? Choose one (check the image to see the questions and question answers)
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Chemistry
1 answer:
andrezito [222]3 years ago
6 0
Q6. 3
Q7. 3
Q8. pH
Q18. 3
Q19. 3
Q20. 4
Hope this helped??
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Akimi4 [234]
O is what should go in the blank. O stands for Oxygen.
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How many protons and electrons are present in Au+?
balandron [24]

Answer:

Protons: 79

Electrons: 78

Explanation:

1. The number of protons is the atomic number (The atomic number for Au on the periodic table is 79)

2. Since the charge is +1 (positive) it means that there's one more proton than electrons. So, 79-1 = 78 electrons

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HELP ME NOW ASAP PLEASE, 10 POINTS HURRY
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Which of those depend on mayfly nymphs. In other terms which animal eats mayfly nymphs?

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Name this compound Cr2(CO3)3
kiruha [24]

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Molecular Weight

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Chromium(III) Carbonate Cr2(CO3)3 Molecular Weight -- EndMemo.

5 0
3 years ago
1. Oxygen was discovered by Joseph Priestley in 1774 when he heated mercury (II) oxide, HgO, to decompose it to form its constit
Tomtit [17]

Answer:

1. 7.81 moles HgO

2. n = mass/molar mass = (4000 g)/(159.69 g/mol) = 25.05 mol.

Explanation:

How many moles of mercury (II) oxide are needed to produce 125 g of oxygen?

2HgO ==> 2Hg + O2  

125 g O2 x 1 mol O2/32 g x 2 mol HgO / mol O2 = 7.81 moles HgO

------------------------------------------------------------------------------------------------------------

If 4000 g of Fe2O3 is available to react, how many moles of CO are needed?

The no. of moles of CO are needed = 75.15 mol.

Fe₂O₃ + 3CO → 2Fe + 3CO₂,

It is clear that 1 mol of Fe₂O₃ reacts with 3 mol of CO to produce 2 mol of Fe and 3 mol of CO₂.

If 4.00 kg Fe₂O₃ are available to react, how many moles of CO are needed?

We need to calculate the no. of moles of 4.00 kg Fe₂O₃:

n = mass/molar mass = (4000 g)/(159.69 g/mol) = 25.05 mol.

Using cross multiplication:

1 mol of Fe₂O₃ need  → 3 mol of CO to react completely, from stichiometry.

25.05 mol of Fe₂O₃ need  → ??? mol of CO to react completely.

The no. of moles of CO are needed = (3 mol)(25.05 mol)/(1 mol) = 75.15 mol.

6 0
3 years ago
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