Answer:
The rocket above the ground is in 44 sec.
Explanation:
Given that,
Initial velocity = 92 m/s
Acceleration = 4 m/s²
Altitude = 1200 m
Suppose, How long was the rocket above the ground?
We need to calculate the time
Using equation of motion
Put the value into the formula
We need to calculate the velocity
Using equation of motion
Put the value into the formula
When the rocket hits the ground,
Then, h'=0
We need to calculate the time
Using equation of motion
Put the value into the formula
When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground
So, the total time will be
Hence, The rocket above the ground is in 44 sec.