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garik1379 [7]
3 years ago
6

A phone cord is 6.48 m long. The cord has a mass of 0.253 kg. A transverse wave pulse is produced by plucking one end of the tau

t cord. The pulse makes four trips down and back along the cord in 0.877 s. What is the tension in the cord
Physics
1 answer:
monitta3 years ago
6 0

Answer:

136.27 N

Explanation:

From the question,

The velocity of the pulse is given as

v = L/t................. Equation 1

Where v = velocity of the pulse, L = total length of the pulse, t = time.

Given: L = 4×2×6.48 (as the pulse makes four tips down and back) = 51.84 m, t = 0.877 s.

substitute into equation 1

v = 51.84/0.877

v = 59.11 m/s.

Using,

But,

v = √(T/m')................... Equation 2

Where T  tension in the cord, m' = mass per unit length of the cord.

make T the subject of the equation

T = v²m'.................... Equation 3

Given: v = 59.11 m/s, m' = 0.253/6.48 = 0.039 kg/m

Substitute into equation 3

T = 59.11²(0.039)

T = 136.27 N

Hence the tension in the cord = 136.27 N

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Answer:

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Explanation:

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3 years ago
.3.3: Populating a vector with a for loop. Write a for loop to populate vector userGuesses with NUM_GUESSES integers. Read integ
Reptile [31]

Answer:

#include <iostream>

#include <vector>

using namespace std;

int main() {

  const int NUM_GUESSES = 3;

  vector<int> userGuesses(NUM_GUESSES);

  int i = 0;

int uGuess = 0;

for(i = 0; i <= userGuesses.size() - 1; i++){

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 userGuesses.at(i) = uGuess;

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cout << endl;

  return 0;

}

Explanation:

First inbuilt library were imported. Then inside the main( ) function, 3 was assigned to NUM_GUESSES meaning the user is to guess 3 numbers. Next, a vector was defined with a size of NUM_GUESSES.

Then a for-loop is use to receive user guess via cin and each guess is assigned to the vector.

8 0
3 years ago
A bug splats against the windshield of a car traveling at high speeds down a backcountry road. Which statement correctly compare
zvonat [6]

Answer:

C. The bug's change in momentum is equal to the car's change in momentum.

Explanation:

As we know by Newton's 2nd law

F = \frac{\Delta P}{\Delta t}

here we have also know that when car hits the bug then force applied by wind shield on the bug is same as the force applied by the bug on the car's wind shield as per Newton's III law

F_{12} = F_{21}

so we know that

\frac{\Delta P_{12}}{\Delta t} = \frac{\Delta P_{21}}{\Delta t}

so we have

\Delta P_{12} = \Delta P_{21}

so correct answer will be

C. The bug's change in momentum is equal to the car's change in momentum.

6 0
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Calculate the radiative and collisional energy losses (in keV/micron) for a 1.9 MeV electron in lead and determine the rad./coll
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Answer:

Explanation:

During an energy transfer, the collision loss for an electron can be determined by using the formula:

Q = \dfrac{4mME }{(m+M)^2}

However; from the total stopping power & power loss of the electron;

\dfrac{radiational \ energy \ loss}{colisional \ energy \ loss } = \dfrac{ZE}{800}

where;

Z = atomic no. for lead = 82

E = 1.9 MeV

∴

radiational energy loss = collisional energy loss  =\dfrac{82 \times 1.9}{800}

= 0.19475

b)

Normally, the traditional lead shielding in its pure shape contains high brittleness. However, the functionality of this carbon group chemical element is useful for protection because it has an excessive density.

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Moreover, the traditional lead with its high density and thickness reduces observation features, in the meantime, the plexiglass is a whole lot higher than the stated.

Finally, plexiglass contains a high dimensional balance with an excessive dielectric constant.

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Non examples of gravity ?
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3 years ago
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