Answer:
19.5 m
Explanation:
Using the equation of motion,
For the first 3 seconds,
s = ut +1/2at².......................... Equation 1
Where t = time, u = initial velocity, a = acceleration, s = distance
Note: Since the car starts from rest, u = 0 m/s.
Given: a = 1.0 m/s, t = 3 s, u = 0 m/s
Substitute into equation 1
s = 0×3+1/2(3)²(1)
s = 9/2
s = 4.5
In the remaining five seconds, at a constant velocity,
s' = vt............. Equation 2
Where v = velocity, t = time.
Recall,
v = u+at
v = 0+1(3)
v = 3 m/s.
Also, t = 5 s.
Substitute into equation 2
s' = 3(5)
s' = 15 m.
Total distance = 15+4.5
Total distance = 19.5 m.
Hence the car travels 19.5 m
Google it and I bet you find the correct answer
Answer:
Venus's very slow rotations rate does not allow a magnetic field to form
Answer: Please see answer in explanation column.
Explanation:
Given that
v≈(331 + 0.60T)m/s
where Temperature, T = 14°C
v≈(331 + 0.60 x 14)m/s
v =331+ 8.4 = 339.4m/s
In our solvings, note that
f= frequency
λ=wavelength
L = length
v= speed of sound
a) Length of the pipe is calculated using the fundamental frequency formulae that
f=v/2L
Length = v/ 2f
= 339.4m/s/ 2 x 494Hz ( s^-1)= 0.3435m
b) wavelength of the fundamental standing wave in the pipe
L = nλ/2,
λ = 2L/ n
λ( wavelength )= 2 x 0.3435/ 1
= 0.687m
c) frequency of the fundamental standing wave in the pipe
F = v/ λ
= 339.4m/s/0.687m=
494.03s^-1 = 494 Hz
d) the frequency in the traveling sound wave produced in the outside air.
This is the same as the frequency in the open organ pipe = 494Hz
e)The wavelength of the travelling sound wave produced in the outside air is the same as the wavelength calculated in b above = 0.687m
f) To play D above middle c . the distance is given by
L =v/ 2 f
= 343/ 2 x 294
=0.583m
Answer:
F = 5226.6 N
Explanation:
To solve a lever, the rotational equilibrium relation must be used.
We place the reference system on the fulcrum (pivot point) and assume that the positive direction is counterclockwise
F d₁ = W d₂
where F is the applied force, W is the weight to be lifted, d₁ and d₂ are the distances from the fulcrum.
In this case the length of the lever is L = 5m, t the distance desired by the fulcrum from the weight to be lifted is
d₂ = 200 cm = 2 m
therefore the distance to the applied force is
d₁ = L -d₂
d₁ = 5 -2
d₁= 3m
we clear from the equation
F = W d₂ / d₁
W = m g
F = m g d₂ / d₁
we calculate
F = 800 9.8 2/3
F = 5226.6 N
