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RUDIKE [14]
3 years ago
11

What part of an electric circuit are the wires that carry the electric current

Physics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

okay so, An electric circuit is a closed loop through which current can  actually flow. All electric circuits must have a voltage source, for example a battery, and a conductor, which is usually  a wire.

how does it flow or how does .current flow in a circuit ? When a wire is connected to battery terminals which is electrons, electrons flow from negative to positive. Electrons have a negative charge in case you didnt know. they are repelled from the negative and attracted to the positive.

if this helped please mark this as brainliest!!! :)

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The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rota
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Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

  • An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion.
  • Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion.
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What was done to test if Comets are responsible for 1/2 the Earth's water?
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✯Hello✯

↪  A satellite was crashed into a comet (on purpose of course)

↪  When it crashed a huge amount of water gushed out

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3 years ago
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Which of the following best describes wind?
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Answer:

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3 years ago
Which statement explains how planets move in orbit as supported by Newton’s first law of motion?
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What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of – 30.0 nC?
Nastasia [14]

Answer:

F=1.26*10^{-3}N

Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

F=\frac{kq_1q_2}{d^2}

We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges(q_1,q_2) and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N

8 0
3 years ago
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