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irinina [24]
3 years ago
9

Given a force of 90 N and a acceleration of 30 m/s/s, what is the object’s mass?

Physics
2 answers:
vladimir2022 [97]3 years ago
7 0
The object’s mass is 3
marishachu [46]3 years ago
3 0
3 is the mass of the object
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How are light waves used to bring far away objects into view and how does the eye translate them?
adelina 88 [10]

Answer:

When focused light is projected onto the retina, it stimulates the rods and cones. The retina then sends nerve signals are sent through the back of the eye to the optic nerve. The optic nerve carries these signals to the brain, which interprets them as visual images.

Explanation:

Hope it will help u

5 0
2 years ago
Which of Newton’s Laws involves mass and acceleration? Question 1 options: 3rd 1st 2nd All of them
Feliz [49]
The answer would be Newton’s Second Law
6 0
3 years ago
Read 2 more answers
How much current flows through a 100- ohm device connected to a 1.5- volt battery​
Stolb23 [73]

Answer:

0.015A

Explanation:

I=V/R

=1.5/100

0.015A

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5 0
2 years ago
A 2-kg toy car accelerates from 5 to 10 m/s.
andre [41]
<h3><u>Full Question:</u></h3>

A 2-kg toy car accelerates from 5 to 10 m/s in 2 seconds. Find the applied force.

<h2><u>Answer:</u></h2>

Force applied is 5\frac {kgm} {s^2}.

<h3><u>Explanation:</u></h3>

Force is defined as something which changes or tends to change the velocity of a body. And acceleration is defined as the rate of change of velocity of a body per time. Both of them are vector quantities.

The initial velocity of the body = 5 m/s.

The final velocity of the body = 10 m/s.

So the change in velocity = 10 - 5 m/s = 5m/s.

Time period = 2 seconds.

So acceleration =\frac52 m/s^2= 2.5 m/s^2

The force is defined as the product of mass and acceleration of the body.

Mass of body = 2 kg.

So, force applied =  2 \times 2.5 kgm/s^2. =5kgm/s^2.

4 0
3 years ago
A ball has an electric charge of +1.5 × 10-9 coulombs. At what distance from the ball's center is the electric field strength eq
Veronika [31]
F = kq1q2/r<span>2
Where,
F - Coulomb Force
k - constant value which is equal to </span>8.98 × 10^9<span> newton square metre per square coulomb
q1 and q2 -  two electric charges
r - distance.

5.8 * 10^5 = 1.5 * 10^-9 / r^2
</span><span>5.8 * 10^5 r^2 = 1.5*10^-9
</span>r^2 = 0.0000258620
r = 0.0050854694

So the distance is equal to 5.09 x 10^-3 
3 0
3 years ago
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