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Basile [38]
3 years ago
11

A box is at rest on a slope

Physics
1 answer:
matrenka [14]3 years ago
6 0

Answer:

170 N

Explanation:

The following data were obtained from the question:

Mass (m) = 20 Kg

Angle (θ) = 30°

Acceleration due to gravity (g) = 9.8 m/s²

Weight (W) =?

The perpendicular component of the weight can be obtained by using the following formula:

W = mg × Cosθ

W = 20 × 9.8 × Cos 30

W = 196 × 0.866

W = 169.7 ≈ 170 N

Therefore, perpendicular component of the weight is 170 N

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Amazon rectangular bar of low carbon steel A-36 is exposed to an axial strees of 150 MPa. What is the original length of the bar
kolbaska11 [484]

Answer:

1.8m

Explanation:

Let the Elastics of the steel ASTM-36 E = 200000 MPa

The strain of the bar when subjected to 150 MPa is

\epsilon = \frac{\sigma}{E} = \frac{150}{200000} = 0.00075

Therefore, if the bar elongates by 1.35 mm, then the original length L would be:

\epsilon = \frac{\Delta L}{L}

L = \frac{\Delta L}{\epsilon} = \frac{1.35}{0.00075} = 1800 mm or 1.8m

5 0
3 years ago
A wire loop of radius 0.37 m lies so that an external magnetic field of magnitude 0.35 T is perpendicular to the loop. The field
Galina-37 [17]

Answer:

168.57 mV

Explanation:

Initial magnetic flux = BA , B magnetic field and A is area of loop

= .35 x 3.14 x .37²

= .15 Weber

Final magnetic flux

= - .2 x 3.14 x .37²

= -  .086 Weber

change in flux

.15 +  .086

= .236 Weber

rate of change of flux

= .236 / 1.4

= .16857 V

= 168.57 mV

5 0
3 years ago
Gold has a density of 19300 kg/m³. Calculate the mass of 0.02 m³ of gold in kilograms.
hjlf

Answer:

Mass = 386 kg

Explanation:

<u><em>Density = Mass / Volume</em></u>

Mass = Density × Volume

Where D = 19300 kg/m³ , V = 0.02 m³

<em>Putting the given in the above formula</em>

Mass = 19300 × 0.02

Mass = 386 kg

7 0
3 years ago
Read 2 more answers
You have just been made the CEO (Chief Executive Officer) of a major company (like Amazon or Tesla). Now, you have the power to
12345 [234]

When I become a CEO (Chief Executive Officer) of a large company (like Amazon or Tesla), I would make the company more humane, with great parameters of working conditions, paying good salaries, so we would improve production and people would be happier , being an example to the whole world of a company that values and respects its employees.

<h3>Who is the CEO?</h3>

The CEO is essentially the highest-ranking executive in the company. He has most of the power. He reports directly to the board of directors. On the other hand, the president is below the CEO in the company hierarchy.

<h3>What does the CEO of a company do?</h3>

Direct the company's next steps through strategic planning; Take care, together with directors and shareholders of the company's health; Implement or modify processes within the company or sectors; Represent and relate to external audiences.

With this information, we can conclude that  I would make the company more humane, with great parameters of working conditions

Learn more about CEO in brainly.com/question/14747141

#SPJ1

5 0
2 years ago
A parallel-plate capacitor stores charge Q. The capacitor is then disconnected from its voltage source, and the space between th
Stells [14]

Answer:

The relationship between the initial stored energy PE_{i} and the stored energy after the dielectric is inserted PE_{f} is:

c) PE_{f} =0.5\ PE_{i}

Explanation:

A parallel plate capacitor with C_{o} that is connected to a voltage source V_{o} holds a charge of Q_{o} =C_{o} V_{o}. Then we disconnect the voltage source and keep the charge Q_{o} constant . If we insert a dielectric of \kappa=2 between the plates while we keep the charge constant, we found that the potential decreases as:

                                                     V=\frac{V_{o}}{\kappa}

The capacitance is modified as:

                                              C=\frac{Q}{V} =\kappa\frac{Q_{o}}{V_{o}}=\kappa\ C_{o}

The stored energy without the dielectric is

                                               PE_{i}=\frac{1}{2}\frac{Q_{o}^{2}}{C_{o}}=\frac{1}{2}C_{o}V_{o}^{2}

The stored energy after the dielectric is inserted is:

                                               PE_{f}=\frac{1}{2}\frac{Q^{2}}{C}=\frac{1}{2}CV^{2}

If we replace in the above equation the values of V and C we get that

                                         PE_{f}=\frac{1}{2}\kappa\ C_{o}(\frac{V_{o}}{\kappa})^{2}=\frac{1}{\kappa}(\frac{1}{2}C_{o}V_{o}^{2})

                                                   PE_{f} =\frac{PE_{i}}{\kappa}

Finally

                                                  PE_{f} =0.5\ PE_{i}

                                               

                                     

5 0
3 years ago
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