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sasho [114]
4 years ago
14

How do human break N2 into a useable form

Physics
1 answer:
Fiesta28 [93]4 years ago
6 0
A process known as fixation<span>. the majority of nitrogen is fixed by </span>bacteria<span>, most of which are </span>symbiotic<span> with plants</span>


<span />
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Which of these can Waves transfer energy through?
professor190 [17]
Hey which type of wave are u talking about a sound wave a electromagnetic one ?
5 0
3 years ago
The charge that passes a cross-sectional area A=10-4 m2 varies with time according
Anarel [89]

Answer:

Current = dQ/dt

or I = dQ/dt

Where I represents current.

Which is the rate of flow of charge.

Q=4 + 2t + t²

dQ/dt = 2 + 2t --- This is the relation that gives the instantaneous current.

At time t=2sec

dQ/dt = I = 2 + 2t

= 2 + 2(2)

=2 + 4

= 6A.

6 0
3 years ago
A student carries a backpack for one mile. Another student carries the same backpack for two miles
Svetllana [295]

Answer:

Compared to the first student, the second student did twice as much work as the first student.

Explanation:

The work done by the first student will be equal to the Force exerted by the backpack on the student carrying it multiplied by one mile (Distance).  The work done by the second student will be equal to the Force exerted by the backpack on the student carrying it multiplied by two miles (Distance).

3 0
3 years ago
Pressure and temperature ______ with depth below Earth’s surface.
ivolga24 [154]

Answer:

Pressure increases as you move deeper below earth's surface.

Tempurature  increases as you move deeper below earth's surface.

Hope this helps!

Explanation:

3 0
4 years ago
You are loading a toy dart gun, which has two settings, the more powerful with the spring compressed twice as far as the lower s
Amiraneli [1.4K]

Answer:

option A

Explanation:

given,

compression for lower setting = x

work done to compress in lower setting = 5 J

compression in higher setting, x' = 2 x

work done in higher setting = ?

Work done in compression of spring at lower setting

W = \dfrac{1}{2}kx^2

5 = \dfrac{1}{2}kx^2............(1)

Work done in compression of spring at higher setting

W' = \dfrac{1}{2}kx'^2

W'= \dfrac{1}{2}k(2x)^2

W'= 4\times \dfrac{1}{2}kx^2

W'= 4\times W

from equation (1)

W'= 4\times 5

    W' = 20 J

Work take for the higher setting is equal to 20 J

Hence, the correct answer is option A

4 0
3 years ago
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