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alex41 [277]
3 years ago
8

To become positively charged an átom must

Physics
2 answers:
Ivanshal [37]3 years ago
7 0

Lose electrons because they have a negative charge.

Elodia [21]3 years ago
5 0
Lose because they have a negative charge
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What is the resultant force of the free body diagram?
GaryK [48]

1) Magnitude of the net force: 20.8 N

2) Angle: 35.2^{\circ} clockwise from positive x-direction

Explanation:

1)

First of all, we need to find the components of the resultant force along the horizontal and vertical direction.

We observe that there are two forces acting along the horizontal direction:

F_1=33 N\\F_2 = 16 N

We notice that they act in opposite directions, so the net force in the horizontal direction is the difference between these two forces:

F_x =F_1-F_2=33-16=17 N (to the right)

Instead, there is only one force acting in the vertical direction, so the net force in the vertical direction is:

F_y=F_3=12 N (downward)

Therefore, the magnitude of the net force can be found by using Pythagorean's theorem:

F=\sqrt{F_x^2+F_y^2}=\sqrt{17^2+12^2}=20.8 N

2)

Now we have to find the angle of the resultant net force. We can do it by using the following equation:

tan \theta = \frac{F_y}{F_x}

where

\theta is the angle, measured as clockwise from the positive x-direction (because the vertical net force is downward)

F_y = 12 N is the vertical net force

F_x=17 N is the horizontal net force

Solving, we find:

tan \theta=\frac{12}{17}=0.706

And so the angle is

\theta=tan^{-1}(0.706)=35.2^{\circ}

In a direction down with respect to the right.

Learn more about forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

About addition of vectors:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

4 0
3 years ago
A 1.50 V potential difference is maintained across a 1.50 m wire that has a cross-sectional area of 0.600 mm2. How much power is
Goshia [24]

Given that the potential difference is V = 1.5 V.

The length of the wire is l = 1.5 m.

The cross-sectional area is

\begin{gathered} A\text{ = 0.6 }mm^2 \\ =0.6\times10^{-6}m^2 \end{gathered}

The resistivity of the wire is

\rho\text{ = 5.25}\times10^{-8}\Omega\text{ m }

We have to find the power dissipated in the wire.

First, we need to calculate resistance.

The resistance can be calculated as

\begin{gathered} R\text{ = }\rho\frac{l}{A} \\ =5.25\times10^{-8}\times\frac{1.5}{0.6\times10^{-6}} \\ =0.13125\Omega \end{gathered}

The formula to calculate power is

P\text{ =}\frac{V^2}{R}

Substituting the values, the power will be

\begin{gathered} P\text{ = }\frac{(1.5)^2}{0.13125} \\ =17.1\text{ W} \end{gathered}

Thus, the power dissipated in the wire is 17.1 W

5 0
2 years ago
Which of the following account for the difference between radio waves , infrared waves, and ultraviolet rays?
gayaneshka [121]

Answer: B

The only difference between these different types of radiation is their wavelength or frequency

Explanation:

5 0
3 years ago
Read 2 more answers
Exercise b) 1) Fill in the blanks with the appropriate word: a) The pressure exerted by the air in atmosphere is called b) Press
Tanzania [10]

Answer:

atmospheric pressure

b)

c)increases

d) ....

7 0
3 years ago
A 10.0 kg box is dragged 5.00 meters across a rough horizontal floor by a rope with a tension
Lemur [1.5K]

Answer:

Explanation:

Net work done on the box = increase in kinetic energy

= 1 / 2 x 10 ( 5² - 3² )

= 80 J .

5 0
3 years ago
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