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Gnom [1K]
3 years ago
7

Qliestion 5 (1 point)

Physics
1 answer:
love history [14]3 years ago
4 0

Answer:

-3.33 ms^-2

Explanation:

Hope it helps

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What effect would thick cloud cover have on the temperature of earth's surface?
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Thick cloud cover over the whole of planet Earth would block out sunlight from reaching the surface.  This means that it would lower the temperature on the Earth's surface.
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Explain one way the water cycle affects climate. Use complete sentences.
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When water vaporizes into the air, it becomes humid out.
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Why are objects that fall near earth’s surface rarely in free fall?
Sloan [31]

Answer:

Because of the presence of air resistance

Explanation:

When an object is in free fall, ideally there is only one force acting on it:

- The force of gravity, W = mg, that pushes the object downward (m= mass of the object, g = acceleration of gravity)

However, this is true only in absence of air (so, in a vacuum). When air is present, it exerts a frictional force on the object (called air resistance) with upward direction (opposite to the motion of free fall) and whose magnitude is proportional to the speed of the object.

Therefore, it turns out that as the object falls, its speed increases, and therefore the air resistance acting against it increases too; as a result, the at some point the air resistance becomes equal (in magnitude) to the force of gravity: when this happens, the net acceleration of the object becomes zero, and so the speed of the object does not increase anymore. This speed reached by the object is called terminal velocity.

3 0
3 years ago
Question 6 (1 point)
jarptica [38.1K]

Explanation:

decrease,then increase

8 0
3 years ago
If a large housefly 2.4 m away from you makes a noise of 47.0 dB, what is the noise level (in dB) of 5400 flies at that distance
dem82 [27]

Answer:

the noise level of 5400 flies is equal to 84.32 dB

Explanation:

Noise made by house flies = 47 dB from the distance of 2.4 m

to calculate the noise of 5400 flies at a distance of 2.4 m.

the intensity of noise

  10 log_{10}(\dfrac{I}{I_0}) = 47 dB

now,  I' = 5400 I₀

=     10 log_{10}(\dfrac{5400 I}{I_0})

=    10 [log_{10}[5400] +log_{10}(\dfrac{I}{I_0}))      

= 10 ( 3.732 + 4.7 )                            

= 84.32 dB                                          

hence, the noise level of 5400 flies is equal to 84.32 dB

4 0
3 years ago
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