Answer:
 gravitational force
 gravitational force
  electrostatic force
 electrostatic force
Explanation:
The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.
The Mutual force of gravitational pull that they exert on each other can be given as:

where:
 gravitational constant
 gravitational constant  
 are the masses of individual balloons
 are the masses of individual balloons
 the radial distance between the  center of masses of the balloons.
 the radial distance between the  center of masses of the balloons.
But when  there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.
Given as:
 
where:

 are the charges on the individual balloons
 are the charges on the individual balloons
R = radial distance between the charges.
 
        
             
        
        
        
Answer:
theory 
Explanation:
that's why it's called the Big Bang Theory
 
        
                    
             
        
        
        
While Jane is running has a kinetic energy, which is Ek = 1/2*m*v^2 where m is mass and v is velocity  When she grabs a vine, she is going to change the kinetic energy to potential energy.  
We know that potential energy is given by Ep = m*g*h where m is mass, g is gravity constant and h is height  
So while running the kinetic energy is Ek = 1/2 * m * 5.2^2 = 13.52*m 
Then all that energy is used to swing upward and gain potential energy 
Ep = m*g*h = Ek = 13.52*m  
m*9.8*h = 13.52*m 
h = 13.52/9.8 = 1.38 meters  
So Jane will swing 1.38 meters upward
        
             
        
        
        
Answer:
Becomes softer as the temperature rises!
Explanation:
 
        
             
        
        
        
Answer:
A. Final pressure P2 
P2/P1 = (T2/T1)^n/n-1
P1 = 4bar
T1 = 438K
T2 = 300K
Polytropic index, n, = 1.3
P2 = 4 (300/438)^1.3/1.3-1
P2 = 4 (300/438)^4.333
P2 = 4 * 0.19400
P2 = 0.776bar.
B. The work done is; 
W = mR/ n-1 (T1 -T2) 
Where, R = 0.1889kJ/kg.K, m = 1
W = 1 * 0.1889/ 1.3-1 * (438-300)
W = 86.89kJ/kg.
C. The heat transfer, Q
Q = W + ΔU
Q = W + mCv(T2-T1), where Cv of nitrogen is 0.743kj/kgk
Q = 86.89 + 1 * 0.743 (300-438)
Q = 86.89 + (-102.534)
Q = -15.644kJ/K
Q = 15.64kJ/K