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alexira [117]
3 years ago
14

Using triangle A B C as the pre-image and the origin as the center of dilation, which coordinate point is not a coordinate of a

dilation that uses a scale factor of 4?
Coordinate plane ranging from negative five to five on the x and y axes. Point A is at (negative one, three), point B is at (two, one) and point C is at (negative two, one). The three points are connected to form a triangle.

Question 4 options:

begin ordered pair 4 comma 12 end ordered pair


begin ordered pair negative 4 comma 12 end ordered pair


begin ordered pair 8 comma 4 end ordered pair


begin ordered pair negative 8 comma negative 4 end ordered pair

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
3 0

Answer:

The correct option is:

begin ordered pair 4 comma 12 end ordered pair i.e. (4,12).

Step-by-step explanation:

We are given the coordinates of the point A,B and C of the triangle ΔABC as:

A(-1,3) , B(2,1) and C(-2,-1).

Now it is given that there is dilation of this triangle about the origin with a scale factor of 4.

This means that the change in the coordinates after the transformation is given by the rule:

(x,y) → (4x,4y)

As A → A' , B → B' and C → C'

Hence the coordinates A',B' and C' are given by:

A' are (4×-1,4×3)=(-4,12)

B' are (4×2,4×1)=(8,4)

and C' are (4×-2,4×-1)=(-8,-4).

<em>Hence the coordinate point which is not a coordinate of dilation is:</em>

<em>begin ordered pair 4 comma 12 end ordered pair  i.e. (4,12)</em>

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Answer:

Part 1) sin(B)=\frac{21}{29}

Part 2) csc(A)=\frac{29}{20}

Part 3) cot(A)=\frac{21}{20}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

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tan(A)=\frac{20}{21}

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cot(A)=\frac{21}{20}

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3 years ago
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