Answer:
Required probability is 0.19
Step-by-step explanation:
The two-way table for the given data is,
Fiction Non-Fiction Total
9th grade 35 8 43
10th grade 52 12 64
Total 87 20 107
It is required to find the probability of the students who prefer to read non-fiction novels, given that they are in 9th grade.
That is, to find the conditional probability
.
Now, 
So, we get,

<h3>Thus, the required probability is 0.19.</h3>
Answer:

Find the midsegment of the triangle which is parallel to CA.

Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

~
Answer:
6 dollars per hour
Step-by-step explanation:
We can set up and solve an equation to answer this question. For this problem, let x stand for the amount he earned per hour. The equation that represents this situation is 3.2x + 4.3x = 45. The first term represents monday and the second represents tuesday. When these add up they should equal 45 because that is the total amount he made. To find his pay per hour, solve for x.
First, combine the like terms
Next, divide both sides by 7.5
Answer:

Step-by-step explanation:
The applicable rules of exponents are ...

Your ratio simplifies to ...

_____
Please note that simplifying the constants, -8/10 to -4/5, eliminates half the answer choices. Since exponents are only multiplied when a power is raised to a power, you can pretty much eliminate the second choice as being unreasonable. ((a^b)^c = a^(bc))