Based on the attached image:
- The name of the longitude line that passes through point A is the International Date Line
- The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
- The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
- Longitude 120° is B
- Solar time at Point B is 4 pm
- The location will correspond to any point on the same latitude as A
<h3>What are lines of longitude?</h3>
Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.
Longitude lines divide the earth into semi-circles.
Longitude lines are known as meridians and each meridian measures one arc degree of longitude.
Considering the attached image:
- The name of the longitude line that passes through point A is the International Date Line
- The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
- The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
- Longitude 120° is B
- Solar time at Point B is 4 pm
- the location will correspond to any point on the same latitude as A
In conclusion, longitude lines are imaginary lines and run from North to South on the earth.
Learn more about lines of longitude at: brainly.com/question/1939015
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Answer:
a.
Explanation:
cuz whenever the ball was traveling up the staircase it was building up energy to use (potential energy) unlike b.
Answer:
Acceleration = 5.77 m/s²
Distance cover in 13 seconds = 487.56 meter
Explanation:
Given:
Final velocity of mobile device = 75 m/s
initial velocity of mobile device = 0 m/s
Time taken = 13 seconds
Find:
Acceleration
Distance cover in 13 seconds
Computation:
v = u + at
75 = 0 + (a)(13)
13a = 75
a = 5.77
Acceleration = 5.77 m/s²
s = ut + (1/2)(a)(t²)
s = (0)(t) + (1/2)(5.77)(13²)
Distance cover in 13 seconds = 487.56 meter
Answer:
a = 1.152s
b = 0.817 m
c = 7.29m/s
Explanation: let the following
From the first equation of linear motion
V = u+at..........1
parameters be represented as :
t = Time taken
v = Final velocity
a = Acceleration due to gravity = 9.8m/s²
u = Initial velocity = 4 m/s
s = Displacement
V = 0
Substitute the values into equation 1
0 = 4-9.8(t)
-4 = -9.8t
t = 4/9.8
t = 0.408s
From : s = ut+1/2at^2.........2
S = 4×0.408+0.5(-9.8)×0.408^2
S= 1.632-4.9(0.166)
S = 1.632-0.815
S = 0.817m
Her highest height above the board is 0.817 m
Total height she would fall is 0.817+1.90 = 2.717 m
From equation 2
s = ut+1/2at^2
2.717 m = 0t+0.5(9.8)t^2
2.717 m = 0+4.9t^2
2.717 m = 4.9t^2
2.717/4.9 = t^2
0.554 =t^2
t =√0.554
t = 0.744s
Hence, her feet were in the air for 0.744+0.408seconds
= 1.152s
Also recall from equation 1
V= u+at
V = 0+9.8(0.744)
V = 7.29m/s
Hence, the velocity when she hits the water is 7.29m/s
Finally,
a = 1.152s
b = 0.817 m
c = 7.29m/s
