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Aliun [14]
3 years ago
15

An object suspended from a spring vibrates with simple harmonic motion. Part A At an instant when the displacement of the object

is equal to one-fourth the amplitude, what fraction of the total energy of the system is kinetic
Physics
1 answer:
SOVA2 [1]3 years ago
5 0

Complete Question

An object suspended from a spring vibrates with simple harmonic motion.

a. At an instant when the displacement of the object is equal to one-half the amplitude, what fraction of the total energy of the system is kinetic?

b. At an instant when the displacement of the object is equal to one-half the amplitude, what fraction of the total energy of the system is potential?

Answer:

a

The fraction of the total energy of the system is kinetic energy  \frac{KE}{T}  = \frac{3}{4}

b

The fraction of the total energy of the system is potential energy  \frac{PE}{T} =  \frac{1}{4}

Explanation:

From the question we are told that

    The displacement of the system is  e =  \frac{a}{2}

where a is the amplitude

     

Let denote the potential energy as PE  which is mathematically represented as

           PE  = \frac{1}{2} * k* x^2

=>       PE  = \frac{1}{2} * k* [\frac{a}{2} ]^2

          PE  = k* [\frac{a^2}{8} ]

 Let denote the total energy as T which is mathematically represented as

           T = \frac{1}{2}  *  k * a^2

Let denote the kinetic energy as  KE  which is mathematically represented as

      KE =  T -PE

  =>     KE =k [ \frac{a^2}{2}  - \frac{a^2}{8} ]

=>      KE =k [ \frac{3}{8} a^2  ]

Now the fraction of the total energy that is kinetic energy is  

       \frac{KE}{T}  = \frac{ \frac{3ka^2}{8} }{\frac{ka^2}{2} }

       \frac{KE}{T}  = \frac{3}{4}

Now the fraction of the total energy that is potential energy is  

      \frac{PE}{T} =  \frac{\frac{k a^2}{8} }{\frac{k a^2}{2} }

      \frac{PE}{T} =  \frac{1}{4}

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