3 years ago

A 0.5 kg cheeseburger is lobbed at a particularly unhappy customer with a force of 10 N.

Physics

1 answer:

aleksley [76]3 years ago

6 0

The acceleration that the cheeseburger experienced is 20 m/s^2.

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A 15 kg runaway grocery cart runs into a spring with spring constant 230 N/m and compresses it by 56 cm .What was the speed of t

liubo4ka [24]

To solve this problem we will apply the concepts related to the conservation of kinetic energy and elastic potential energy. Thus we will have that the kinetic energy is

$KE = \frac{1}{2} mv^2$

And the potential energy is

$PE = \frac{1}{2} kx^2$

Here,

m = mass

v = Velocity

x = Displacement

k = Spring constant

There is equilibrium, then,

KE = PE

$\frac{1}{2} mv^2 = \frac{1}{2} kx^2$

Our values are given as,

$x=0.56m\\k=230N/m\\m=15kg$

Replacing we have that

$\frac{1}{2} (15)v^2 = \frac{1}{2} (230)(0.56)^2$

$v = 2.19m/s$

Therefore the speed of the cart is 2.19m/s

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4 years ago

A particle of charge of +3.40 ✕ 10−6 C is 17.5 cm distant from a second particle of charge of −2.00 ✕ 10−6 C. Calculate the magn

Karolina [17]

Answer:

0.47 N

Explanation:

q1 = 3.4 x 10^-6 C

q2 = 2 x 10^-6 C

d = 17.5 cm = 0.175 m

The electrostatic force is given by

$F=\frac{Kq_{1}q_{2}}{d^{2}}$

$F=\frac{9\times10^{9}\times3.4\times 10^{-6}\times 2\times 10^{-6}}{0.175\times 0.175}$

F = 0.47 N

Thus, the force is 0.47 N.

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3 years ago

How do the forces acting on a boat compare to the force acting on a plane ?

erica [24]

Answer:

on there boat there will two main forces act 1,upthrust which comes from water and air and other side on the plane air and gravity.

Explanation:

7 0

3 years ago

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Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76

kicyunya [14]

If I’m understanding the question then 11.76cm^2 in two sig figs is 12cm^2. I don’t see a part c to this question though so if I’m not giving you the answer you need please advise and I will answer what you need! Thank you!!

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4 years ago

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If the period of a spring is 5 seconds what is the frequency

Scilla [17]

Answer:

C. 0.2 Hertz

Explanation:

The frequency of a spring is equal to the reciprocal of the period:

$f=\frac{1}{T}$