All categories

3 years ago

a rock with mass of 5kg is carried up a small hill 10 meters high. how much work had to be done in carrying the rock up hill

Physics

1 answer:

aliya0001 [1]3 years ago

6 0

Answer:

490Nm

Explanation:

Given the following :

Mass of rock = 5kg

Height or distance = 10 meters

A rock with mass of 5kg is carried up a small hill 10 meters high. how much work had to be done in carrying the rock up hill?

Workdone is product of force and distance.

Workdone = force * distance

Recall :

Force = mass * acceleration due to gravity (g)

g = 9.8m/s^2

Force = 5 * 9.8 = 49 N

Therefore,

Workdone = 49 × 10 = 490Nm

You might be interested in

Ask Your Teacher In a choir practice room, two parallel walls are 4.00 m apart. The singers stand against the north wall. The or

igomit [66]

Answer: 4m

Explanation:

Since the angle of incidence of a plane mirror can be anything from 0 to 90°

Assuming that the place is a perfectly square 4×4m room

The incident ray would be 45° for the choir(object) at a 4m distance, this is still within the range of values.

We do not forget also, that the focal length of a plane mirror is infinity, the organist would in fact see farther than 4m if need be. And wider

5 0

3 years ago

Assume that a cloud consists of tiny water droplets suspended (uniformly distributed,

aev [14]

9.8 ms^-2 is acceleration

4 0

3 years ago

If you are standing at a beach on Earth at the same time that the shadow of the moon falls across your location, what event woul

Tcecarenko [31]

A solar eclipse .....................

5 0

3 years ago

A vector is In English

zzz [600]

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.

3 0

3 years ago

Two +1 C charges are separated by 30000 m, what is the magnitude of the force?

Kipish [7]

Answer:

The magnitude of the force is 10 N

Explanation:

Coulomb's Law

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

$\displaystyle F=k\frac{q_1q_2}{d^2}$

Where:

$k=9\cdot 10^9\ N.m^2/c^2$

q1, q2 = the objects' charge

d= The distance between the objects

We have two identical charges of q1=q2=1 c separated by d=30000 m, thus the magnitude of the force is:

$\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}$

F = 10 N

The magnitude of the force is 10 N

7 0

3 years ago