First, let calculate the volume of the rod shaped-bacteria:
S = length of the bacteria * surface of its side = 4.1 * (0.45 *0.45 * 3.14) = 2.6 µm3
Now, let's convert the moles into molecules (with Avogadro's law):
0.0037mol/L = 0.0037 * 6.023 *10^23 = 2.22 *10^21 molecules / L
Now let's convert The volume and the concetrnation into µm3 (molecules / µm3)
1 L = 1 dm3 = 1000 cm3 = 1000000 mm3 = 10^9 µm3
so 2.22 *10^21 molecules / L = 2.22 10^ 12 molecules / µm3
The answer is 2.22 10^ 12 molecules / µm3
The answer should be an unconformity
Answer:
Adenina (30%), citosina (15%), guanina (15%) o timina (40%)
Explicación:
El 30% de las bases nitrogenadas totales lo ocupa la adenina, el 15% de las bases nitrogenadas totales corresponde a la citosina, el 15% de las bases nitrogenadas totales toma la guanina y el 40% restante de las bases nitrogenadas totales lo ocupa la timina. Entonces, al combinar todos estos porcentajes, obtenemos el 100 por ciento del volumen del ácido desoxirribonucleico (ADN).
First is the second and the other one is the 4th
Answer:
Differences in the concentrations of ions on opposite sides of a cellular membrane lead to a voltage called the membrane potential. Typical values of membrane potential are in the range –40 mV to –70 mV. ... These concentration gradients provide the potential energy to drive the formation of the membrane potential.
Explanation:
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