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12345 [234]
2 years ago
12

Function K(v) represents the kinetic energy, in joules, of an object with a mass of 20 kilograms traveling with

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
7 0

Answer:

b. 225 joules

Step-by-step explanation:

plug in 5 m/s and 12.5 m/s in to v and h.

PtichkaEL [24]2 years ago
5 0

Answer:

A. 175 Joules

Step-by-step explanation:

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If 3x − 3 ≤ f(x) ≤ x2 − 3x + 6 for x ≥ 0, find lim x→3 f(x).
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4. 10. 4 Test (CST):
kompoz [17]

Based on the value of the annuity, the amount it earns, and the compounding period, the money paid to Nathan each month will be B. $5,840.62.

<h3>How much will Nathan be paid monthly?</h3>

The amount Nathan will be paid is an annuity because it is constant.

First find the monthly interest and the compounding period in months:
= 4.8/12 months

= 0.4%

Number of compounding periods:

= 20 x 12

= 240 months

The monthly payment is:

Present value of annuity = Annuity x ( 1 - (1 + rate) ^ -number of periods) / rate

900,000 = A x ( 1 - (1 + 0.4%)⁻²⁴⁰) / 0.375%

900,000 = A  x 154.0932

A = 900,000 / 154.0932

= $5,840.62.

Find out more on the present value of an annuity at brainly.com/question/25792915.

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4 0
2 years ago
Read 2 more answers
Consider the quadratic functions represented below. Function #1 Function #2 x y -1 14 -0 6 1 2 2 2 3 6 4 14 Which function has a
Harrizon [31]

Answer:

Function <u>#2</u> has a greater minimum.

#3 < #1 < #2

Step-by-step explanation:

In the picture attached, the question is shown.

The minimum of Function #1 is located at (3, -1). This is seen in the picture.

The minimum of Function #2 is located at (1.5, 1). We can see in the table that the function is symmetric respect 1.5 (half-point between 1 and 2).

The function y = x² + 3x - 4 has its minimum at its vertex:

x-coordinate of vertex: x = -b/(2a) = -3/(2*1) = -1.5

y-coordinate of vertex: y = (-1.5)² + 3(-1.5) - 4 = -6.25

So, the minimum of Function #3 is located at (-1.5, -6.25)

4 0
3 years ago
What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
2 years ago
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