Ok i can help you solve this problem do you know the formula for quadratic equations
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Based on the value of the annuity, the amount it earns, and the compounding period, the money paid to Nathan each month will be B. $5,840.62.
<h3>How much will Nathan be paid monthly?</h3>
The amount Nathan will be paid is an annuity because it is constant.
First find the monthly interest and the compounding period in months:
= 4.8/12 months
= 0.4%
Number of compounding periods:
= 20 x 12
= 240 months
The monthly payment is:
Present value of annuity = Annuity x ( 1 - (1 + rate) ^ -number of periods) / rate
900,000 = A x ( 1 - (1 + 0.4%)⁻²⁴⁰) / 0.375%
900,000 = A x 154.0932
A = 900,000 / 154.0932
= $5,840.62.
Find out more on the present value of an annuity at brainly.com/question/25792915.
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Answer:
Function <u>#2</u> has a greater minimum.
#3 < #1 < #2
Step-by-step explanation:
In the picture attached, the question is shown.
The minimum of Function #1 is located at (3, -1). This is seen in the picture.
The minimum of Function #2 is located at (1.5, 1). We can see in the table that the function is symmetric respect 1.5 (half-point between 1 and 2).
The function y = x² + 3x - 4 has its minimum at its vertex:
x-coordinate of vertex: x = -b/(2a) = -3/(2*1) = -1.5
y-coordinate of vertex: y = (-1.5)² + 3(-1.5) - 4 = -6.25
So, the minimum of Function #3 is located at (-1.5, -6.25)
Answer:
the positive slope of the asymptote = 5
Step-by-step explanation:
Given that:

Using the standard form of the equation:

where:
(h,k) are the center of the hyperbola.
and the y term is in front of the x term indicating that the hyperbola opens up and down.
a = distance that indicates how far above and below of the center the vertices of the hyperbola are.
For the above standard equation; the equation for the asymptote is:

where;
is the slope
From above;
(h,k) = 11, 100
= 100
a = 
a = 10

b = 
b = 2


y = 5x-53 , -5x -57
Since we are to find the positive slope of the asymptote: we have
to be the slope in the equation 
= 
= 5
Thus, the positive slope of the asymptote = 5