1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
12345 [234]
3 years ago
12

Function K(v) represents the kinetic energy, in joules, of an object with a mass of 20 kilograms traveling with

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
7 0

Answer:

b. 225 joules

Step-by-step explanation:

plug in 5 m/s and 12.5 m/s in to v and h.

PtichkaEL [24]3 years ago
5 0

Answer:

A. 175 Joules

Step-by-step explanation:

You might be interested in
Molly has $60 in a savings account that earns 5% simple interest annually. How much interest will she earn in 6 months?
mrs_skeptik [129]

Answer:

The interest is $1.5 and the amount is $61.5.

Step-by-step explanation:

3 0
3 years ago
Please answer, need it today! ASAP!
Montano1993 [528]

There is no picture.....

???

5 0
3 years ago
Solve for x: x/7 - 3 ≥ 8.
stellarik [79]

Answer:

x is more than or equal to 77

Step-by-step explanation:

5 0
3 years ago
Which equation represents a population of 210 animals that decreases at an annual rate of 14%
soldi70 [24.7K]

Answer:

The equation i.e. used to denote the population after x years is:

P(x) = 490(1 + 0.200 to the power of x

Step-by-step explanation:

This problem could be modeled with the help of a exponential function.

The exponential function is given by:

P(x) = ab to the power of x

where a is the initial value.

and b=1+r where r is the rate of increase or decrease.

Here the initial population of the animals are given by: 490

i.e. a=490

Also, the rate of increase is: 20%

i.e. r=20%

i.e. r=0.20

Hence, the population function i.e. the population of the animals after x years is:

P(x) = 490(1 + 0.200 to the power of x

6 0
3 years ago
What is the simplified expression for,
Nostrana [21]

Here are a few rules you need to know for this equation:

  • Multiplying exponents of the same base: x^m\times x^n=x^{m+n}
  • Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  • Turning a negative exponent to a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

So this is our algebraic expression: \frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}}

Firstly, multiply 3^-4 and 3^2: \frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}

Next, divide:

\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1}

Next, turn the negative exponent into a positive one: 3^12^{-1}= \frac{3}{2}

<u>Your final answer is 3/2, or 1.5.</u>

6 0
3 years ago
Other questions:
  • Kevin plans to watch 3 movies each month. Write an equation to represent the total number of movies n that he will watch in m mo
    11·1 answer
  • Salma suggested they sol a Grande box with 24 cupcakes. The ratio of
    5·2 answers
  • Which of the following represents the area of a rectangle whose length is 3x + 5 and whose width is. x – 2?.
    5·2 answers
  • Find the volume of the oblique cone. Round your answer to the nearest hundredth.
    14·1 answer
  • CAN SOMEONE HELP WITH THE QUESTION IN THE IMAGE.
    12·1 answer
  • Travis performs a dilation of 1/3 on a polygon. He then classifies the image and pre-image as being congruent. Is Travis correct
    14·1 answer
  • During a week in January in Jefferson City, MO, the daily high temperatures were -2˚F, 12˚F, 5˚F, -4˚F, 20˚F, 16˚F, and -12˚F. W
    6·1 answer
  • Need help fast! Solve for y and a if possible please
    12·1 answer
  • The numbers of cookies in a shipment of bags are normally distributed, with a mean of 64
    8·1 answer
  • Anthony is an executive assistant. He makes $15.85 per hour. If he worked 47.50 hours this week, what is his (a) OT pay? What ab
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!