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12345 [234]
2 years ago
12

Function K(v) represents the kinetic energy, in joules, of an object with a mass of 20 kilograms traveling with

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
7 0

Answer:

b. 225 joules

Step-by-step explanation:

plug in 5 m/s and 12.5 m/s in to v and h.

PtichkaEL [24]2 years ago
5 0

Answer:

A. 175 Joules

Step-by-step explanation:

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There are 125 calories in a candy bar. There are 12 candy bars in a box. How many calories are in each box of candy bars?
Andrei [34K]

Answer:

1500

Step-by-step explanation:

8 0
3 years ago
My sister needs help ( casandra0606 )
AleksandrR [38]
The formula for volume of a prism is v=(1/2bh)h so it would be
​(1/2​​ ×7.8×4)×9= 140.4
5 0
3 years ago
The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c
valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is 10.4 \:cm^2

Step-by-step explanation:

The area of a rectangle with length L and width W is A= L\cdot W so the differential of <em>A</em> is

dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W

\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L so

dA=W\Delta L+L \Delta W

We know that each error is at most 0.1 cm, we have |\Delta L|\leq 0.1, |\Delta W|\leq 0.1. To find the maximum error in the calculated area of the rectangle we take \Delta L = 0.1, \Delta W = 0.1 and L=55, W=49. This gives

dA=49\cdot 0.1+55 \cdot 0.1

dA=10.4

Thus the maximum error in the calculated area of the rectangle is 10.4 \:cm^2

4 0
3 years ago
Find the area of the shaded region.
kolbaska11 [484]

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

Put their values accordingly:

\longrightarrow  \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}

<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}

\tt\longrightarrow \: Area = 39 \:  {in}^{2}

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

\rule{225pt}{2pt}

I hope this helps!

8 0
2 years ago
Read 2 more answers
Change the value of n some more, and observe how the lengths of the sides of the image change. Once you've settled on a value fo
Anettt [7]

Answer:

n=3.5 a=1.41 units  a'=4.95 units b3 units b'10.5 units c2.24 units c'=7.83 units

Step-by-step explanation:

This answer assumes that n = 3.5. The ratio of each side length on  to the corresponding side length on  is equal to 3.5. For example, a′ = 3.5a. The ratio is equal to the scale factor, n.

4 0
3 years ago
Read 2 more answers
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