<span>The trajectory (parabola) for a "particle" of water follows from:
h(t) = v(0) sin(angle) t - 1/2 g t^2
x(t) = v(0) cos(angle) t
From the second equation t = x / (v(0) cos(angle) )
and substitution in the first to eliminate t gives the parabola h(x):
h(x) = x tan(angle) - (g/(2v(0)^2 cos(angle)^2) x^2
h(x) = 0 is solved by x=0 (where the trajectory starts) and at
x = 2 v(0)^2 tan(angle) cos^2(angle) / g
x = 2 v(0)^2 sin(angle) cos(angle) / g
x = v(0)^2 sin(2 angle) / g [[ using sin(2 ) = 2 sin(s) cos(s) ]]
For the first question (the 2.0m distance question) you have therefore to solve for angle the equation
2.0= 2*(6.5)^2 sin(2 angle) / 9.81
sin(2 angle) = 0.23
angle = 1/2 * arcsin(0.23) = 6.65 degrees
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<h2><u>Answer:</u></h2>
The statement is True.
<h3><u>Explanation:</u></h3>
A subculture is a gathering of individuals inside a culture that separates itself from the parent culture to which it has a place, frequently keeping up a portion of its establishing standards.
Subcultures build up their own standards and qualities with respect to social, political and sexual issues
Answer:
2 /s north
Explanation:
Given that,
Velocity due North is 8 m/s and due south is 6 m/s
We need to find the magnitude and the direction of the resulting velocity.
Let North is positive and South is negative. When two velocities are in opposite direction, they adds up. So,
It is positive. So, it is in North direction.
The net force on the object as described is; 58.84N
Two forces acting on the object are;
- The <em>applied force and the frictional force.</em>
In essence; the frictional force can be evaluated as;
- Frictional force; = coefficient × Weight of object.
- Frictional force = 0.21 × 20 × 9.8.
- Frictional force = 41.16N
- The Net force = Applied force - frictional force
Net Force = 58.84 N.
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