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zalisa [80]
2 years ago
13

A skateboarder drops in off the top of one side of the half pipe shown below. She does not push off and starts from rest. She st

ands straight as she skates down one side and up the other. She expected to get to the top of other side but didn’t make it. The skateboarder recalled the law of conservation of energy from science and didn’t understand why she didn’t make it to the top of the other side.
Which of the following actions would help the skater reach the top of the other side of the half pipe?


Lubricate the wheels in order to reduce frictional force that is causing the skateboard to lose velocity and bend down while skating off the side and bottom of the half pipe.


Hold a weight in order to increase her mass and cause the skateboard to move with a greater velocity down the half pipe.


Sit on the skateboard in order to lower her center of mass and increase the potential energy of the skateboard.


Push off at the bottom of the half pipe in order to replace lost energy and add kinetic energy to the skateboard.
Physics
1 answer:
solong [7]2 years ago
4 0

Answer:

v

Explanation:

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d=42m(-\hat{i})

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For this problem, we need to apply the formulas of constant accelerated motion.

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for the river:

d_r=v*t\\d_r=5m/s*6s\\d_r=30m(\hat{i})

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x=\frac{1}{2}*a*t^2\\\\x=\frac{1}{2}*4.0m/s*(6s)^2\\\\\\x=72m(-\hat{i})

So the final displacement is given by:

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Assume that the body's muscle mechanism can be approximated by a spring with a uniform continuous mass distribution that follows
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Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

<h3>What is the spring constant?</h3>

The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.

  • Spring constant, K = force/extension

Assuming, a body's muscle mechanism is a spring obeying Hooke's law, the effective mass of the spring with mass m is 1/3 of the mass of the spring = m/3

The potential energy that can be stored = ke^2 / 2

where K is spring constant and e is the extension produced.

Therefore, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

Learn more about Hooke's law at: brainly.com/question/12253978

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