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iris [78.8K]
4 years ago
6

When laser light of wavelength 632.8 nm passes through a diffraction grating, the first bright spots occur at ± 17.8 ∘ from the

central maximum. at what angles do the second bright spots occur?
Physics
1 answer:
o-na [289]4 years ago
3 0
The equation we use is mλ=dsinθ for intensity maximas. We are given at the first maximum (m=1), it occurs at 17.8 degrees. Thus we can solve for d by substituting known values into our equation.

(1) (632.8*10^-9m)=dsin(17.8) => d = 2.07*10^-6m

Next we want to find the angle at the second maximum (m=2) so we need to solve for θ.

(2) (632.8*10^-9m) = (2.07*10^-6m)sinθ

θ=37.69 degrees

Hopes this helps!

P.S. I hope this is right. If not sorry in advance.
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Oxygen atoms have six electrons in their outer shells. When two oxygen atoms bond they will form a(n) _____ bond by _____ their
s344n2d4d5 [400]
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What are the units for specific charge?<br> A. C/kg<br> B. C*kg<br> C. kg/C<br> D. 1/C*kg
Stolb23 [73]

Answer:

Option A

Explanation:

Your answer is the first option or "C/kg." C/kg is a ratio for specific charge. C for the charge of the electron, kg for the mass of the electron. To find the specific charge we divide the two, which usually involves scientific notations and simplifying.

<u>Example:</u>
\frac{C}{kg}
\frac{3.4\times10^3C}{2.7\times10^5kg}

Hope this helps.

6 0
2 years ago
A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 10 A, and that o
Katyanochek1 [597]

Answer:

Part a)

P = 1200 Watt

Part b)

P = 480 W

Part c)

\frac{E_{bd}}{E_{vc}} = 5 : 2

Explanation:

Part a)

Power consumed by blow dryer is given as

P = iV

here supply voltage is given as

V = 120 volts

current rating of blow dryer is given as

i = 10 A

P = (120 V)(10 A)

P = 1200 W

Part b)

Power consumed by vacuum cleaner is given as

P = iV

here supply voltage is given as

V = 120 volts

current rating of vacuum cleaner is given as

i = 4 A

P = (120 V)(4 A)

P = 480 W

Part c)

Energy consumed in a given interval of time is given as

Energy = power \times time

now we have to find the ratio of energy consumed in time interval of 11 minutes

so we have

\frac{E_{bd}}{E_{vc}} = \frac{P_{bd} t}{P_{vc} t}

now we have

\frac{E_{bd}}{E_{vc}} = \frac{1200 W\times 11 min}{480 W \times 11 min}

\frac{E_{bd}}{E_{vc}} = 5 : 2

5 0
4 years ago
Young's experiment is performed with light of wavelength 502nm from excited helium atoms. Fringes are measured carefully on a sc
alexandr402 [8]

Answer:

d = 1.30 mm

Explanation:

given,

wavelength of the light source (λ)= 502 nm

slits is separated (d) = ?

distance to form interference pattern(D) = 1.35 m  

20 th fringe

y = 10.4 mm = 0.0104 m

now,separation between to slits

 d = \dfrac{m\lambda\ D}{y}

where y is the fringe width

 d = \dfrac{20 \times 502\times 10^{-9}\ \times 1.35}{0.0104}

 d = \dfrac{13354\times 10^{-9}}{0.0104}

      d = 1.30 mm

separation between to slits is equal to d = 1.30 mm

8 0
3 years ago
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