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blagie [28]
3 years ago
12

ANSWER IN LESS THAN A MIN!! EASY!!​

Physics
2 answers:
snow_lady [41]3 years ago
7 0

Answer:

I think they are both equal in strength but make sure from others

Zina [86]3 years ago
7 0

Answer:

I am pretty sure downward force is stronger.

Explanation:

If you throw something up it goes down, as soon as you throw it up it goes downward. and if you throw something down, if still goes downward.

Mark as brainleist please; i need just one more :P

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How many electrons will a single atom of sulfur with no charge and no bonds have in its valence shell?
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Answer:

There are 6 electrons in the outermost shell.

Explanation:

Sulphur is a non-mettalic element which is in the period 3 and group .6on the periodic table. It has an atomic number of 16 and a Mass number of 32. Atomic number tells you the number of electrons in an electrically neutral atom. It has the electronic configuration of 1s2 2s2 2p6 3s2 3p4.

The orbitals have a formula 2n^2 where n = 0, 1, 2, 3 etc.

In the shells, n = 1 so there are 2 electrons. For n = 2, 2*(2)^2 = 8 electrons. So, 16 - (8 + 2) = 6 electrons in the 3 shell (outermost shell)

Therefore from the electronic confriguration above, there are 6 electrons in the outermost shell.

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A kayaker needs to paddle north across a 100-m-wide harbor. The tide is going out, creating a tidal current that flows to the ea
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Answer:

41.81^{\circ}

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Let Vector \overrightarrow{OA} is the tidal current velocity as shown in the diagram.

In order to travel straight across the harbor, the vector addition of both the velocities (i.e the resultant velocity, \vec {R} must be in the north direction.

Let \overrightarrow{AB} is the speed of the kayaker having angle \theta measured north of east as shown in the figure.

For the resultant velocity in the north direction, the tail of the vector \overrightarrow {OA} and head of the vector \overrightarrow{AB} must lie on the north-south line.

Now, for this condition, from the triangle OAB

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\Rightarrow \theta=41.81^{\circ}

Hence, the kayaker must paddle in the direction of 41.81^{\circ}  in the north of east direction.

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