The rotational speed of the two children is the same.
In fact, it is defined as
where
is the angle covered in the time
. As it can be seen, this quantity does not depend on the distance from the centre, so the rotational speed is 4.0 revolutions per minute for both children.
Because they’re far from each other and the J0523 has lower mass then the UY which is a red dwarf.
The Earth takes very nearly (365 and 1/4) days to go around the sun.
If our calendar always had 365 days, then the year would end and re-start
too soon, and the beginning of Spring (and every other season) would
eventually drift into the months after March.
If our calendar always had 366 days, then the year would end and re-start
too late, and the beginning of Spring (and every other season) would
eventually drift into the months before March.
We can't make calendars with an extra quarter-day in each year. But we
keep them lined up with the real year by saving up the quarters, and adding
one full day to the calendar every 4 years.
Answer:
<em>The tension in the web is 0.017738 N</em>
Explanation:
<u>Net Force</u>
The net force exerted on an object is the sum of the vectors of each individual force applied to an object.
If the net force equals 0, then the object is at rest or moving at a constant speed.
The spider described in the question is hanging at rest. It means the sum of the forces it's receiving is 0.
A hanging object has only two forces: The tension of the supporting string (in our case, the web) and its weight. If the object is in equilibrium, the tension is numerically equal to the weight:
T=W=m.g
The mass of the spider is m=1.81 gr = 0.00181 Kg, thus the tension is:
The tension in the web is 0.017738 N