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ankoles [38]
3 years ago
8

Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}

Mathematics
1 answer:
sashaice [31]3 years ago
3 0

Hey there!

Assuming you meant

5r^2 - 12 = 68

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to add by 12 on each of your sides

5r^2 -12 +12 \\ \\ 68 + 12

5r^2 = 5r^2 \\ \\ 68 + 12 = 80

We get: 5r^2 =80

Now, we have divide by 5 on each of your sides

\frac{5r^2}{5} = \frac{80}{5}

\frac{80}{5}  = 16

We get: r^2 = 16

r = ± \sqrt{16}

Therefore , your answer is:r = ±4

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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Part a.

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If you want the domain in interval notation, then it would be \Big[ -\frac{1}{2} , \infty \Big) which means the interval starts at -1/2 (including -1/2) and then it stops at infinity. So technically it never stops and goes on forever to the right.

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Part b.

I'm going to use "sqrt" as shorthand for "square root"

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f(10) = sqrt(20+1)

f(10) = sqrt(21)

f(10) = 4.58257569 which is approximate

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Part c.

f(x) = sqrt(2x+1)

f(x) = sqrt(2(x)+1)

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f(x+2a) = sqrt(2x+4a+1) .... distribute

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3 years ago
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