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ivann1987 [24]
3 years ago
8

Convert the temperature of the coldest area in freezer, -10 fahrenheit, to degrees celsius and kelvin.

Chemistry
2 answers:
babunello [35]3 years ago
5 0

Answer : The temperature in degree Celsius and Kelvin are, -23.33^oF\text{ and }249.82K

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

where,

^oF = temperature in Fahrenheit

^oC = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273.15+^oC

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in Fahrenheit is, -10

Now we have to determine the temperature in degree Celsius.

^oC=(^oF-32)\times \frac{5}{9}

^oC=(-10^oF-32)\times \frac{5}{9}

^oC=-23.33

Now we have to determine the temperature in Kelvin.

K=273.15+^oC

K=273.15+(-23.33^oC)

K=249.82

Therefore, the temperature in degree Celsius and Kelvin are, -23.33^oF\text{ and }249.82K

aalyn [17]3 years ago
3 0

Answer:

Celsius: 22,33º

Kelvin: 249,8º

Explanation:

In order to calculate you just need to convert the temperature from fahrenheit to celcius and kelvin, you just use the next formulas:

Cº=(ºF-32)(5/9)

Kº=(ºF-32)(5/9)+273,15

Having the formulas you just insert the values into the formulas:

Cº=(-10-32)(5/9)=-23,33º

Kº=(-10-32)(5/9)+273,15=249,8

So -10º fahrenheit are -23,33º celcius and 249,8º kelvin.

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Maslowich

Answer: 4Kcal

Explanation:

H= mcø

M=200g

C= 1 cal/g/°c

Ø= 40-20=20°c

H= 200*1*20= 4000calories= 4Kcal

8 0
2 years ago
A hot air balloon is filled to 1250 m3 at 27 C. At what temperature will the balloon be filled to 1600 m3 if the pressure remain
SSSSS [86.1K]

Answer:

384.2 K

Explanation:

First we convert 27 °C to K:

  • 27 °C + 273.16 = 300.16 K

With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:

  • T₁V₂=T₂V₁

Where in this case:

  • T₁ = 300.16 K
  • V₂ = 1600 m³
  • T₂ = ?
  • V₁ = 1250 m³

We input the data:

300.16 K * 1600 m³ = T₂ * 1250 m³

And solve for T₂:

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7 0
3 years ago
1. If you have 5g of pennies how many dozen pennies do you have?
likoan [24]

Answer:

15.69 dozen

Explanation:

Mass of penny = 5 g

Dozens of penny =..?

Next, we shall convert 5 g to gross. This can be obtained as follow:

3824 g = 1000 gross

Therefore,

5 g = 5 g × 1000 gross / 3824 g

5 g = 1.3075 gross

Thus, 5 g is equivalent to 1.3075 gross.

Finally, we convert 1.3075 gross to dozen. This can be obtained as follow:

1 gross = 12 dozen

Therefore,

1.3075 gross = 1.3075 gross × 12 dozen / 1 gross

1.3075 gross = 15.69 dozen

Thus, 5 g of penny is equivalent to 15.69 dozen

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3 0
3 years ago
The combustion reaction described in part (b) occurred in a closed room containing 5.56 10g of air
ziro4ka [17]

Answer:

Explanation:

Combustion reaction is given below,

C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)

Provided that such a combustion has a normal enthalpy,

ΔH°rxn = -1270 kJ/mol

That would be 1 mol reacting to release of ethanol,

⇒ -1270 kJ of heat

Now,

0.383 Ethanol mol responds to release or unlock,

(c) Determine the final temperature of the air in the room after the combustion.

Given that :

specific heat c = 1.005 J/(g. °C)

m = 5.56 ×10⁴ g

Using the relation:

q = mcΔT

- 486.34 =  5.56 ×10⁴  × 1.005 × ΔT

ΔT= (486.34 × 1000 )/5.56×10⁴  × 1.005

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ΔT= T₂ - T₁

T₂ =  ΔT +  T₁

T₂ = 836.88 °C + 21.7°C

T₂ = 858.58 °C

Therefore, the final temperature of the air in the room after combustion is 858.58 °C

4 0
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