1) Chemical equation
2Al + 6 HCl ---> 2Al Cl3 + 3 H2
2) molar ratios
2 mol Al : 3 moles H2
3) Proportion
2 mol Al / 3mol H2 = x / 9 mol H2
4) Solve for x
x = 9 mol H2 * 2 mol Al / 3 mol H2 = 6 mol Ag
Answer: 6 moles
Answer:
To make one gallon of 5% methyl alcohol we require 115.2oz of water and 12.8oz of 50% methyl alcohol solution
Explanation:
Required solution = 1 gallon of 5% methyl alcohol or1 gallon 5/100 moles per dm3 of methyl alcohol
Number of moles in required solution = 0.05moles/dm3 × 1gallon
Where 1 gallon = 0.00378dm3
= 0.05moles/dm3 × 0.00378dm3 = 1.892×10-4 moles
The quantity of the 50% solution with Paul required is given by
50% = 50/100 = 0.5 moles/dm3
Volume of 50% solution of methyl alcohol that contains 1.892×10-4 moles
= concentration = (Number of moles)/(volume of dm3) of solution thus
Volume of solution = (Number of moles)/(concentration)
1.892/0.5 =3.785×10-4dm3 of the 50% solution is required to make 1 gallon of 5% solution
3.785×10-4dm3 = 12.8oz
Thus to make 1 gallon or 128oz solution of 5% alcohol requires
128oz - 12.8 oz = 115.2oz of water and 12.8oz of 50% methyl alcohol solution
Answer : The value of for the final reaction is, 184.09
Explanation :
The equilibrium reactions in aqueous solution are :
(1)
(2)
The final equilibrium reaction is :
Now we have to calculate the value of for the final reaction.
Now equation 1 is multiply by 2 and reverse the equation 2, we get the value of final equilibrium reaction and the expression of final equilibrium constant is:
Now put all the given values in this expression, we get :
Therefore, the value of for the final reaction is, 184.09
Answer:
It is made of atoms that are covalently bonded together.
Explanation:
For example the carbonate ion CO3++.
The carbon and oxygen atoms are held together by covalent bonds.