What mass in grams of nitric acid is required to react with 750 g C7H8?
1 answer:
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Answer: 25.13 g of and 20.56 g of
will be produced from 45.70 g of
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
1 mole of produce = 1 mole of
Thus 0.571 moles of will require=
of
Mass of
1 mole of produce = 2 moles of
Thus 0.571 moles of will require=
of
Mass of
Thus 25.13 g of and 20.56 g of
will be produced from 45.70 g of
The Correct pair of Element and it's symbol ~
- Mercury - Hg
- Sodium - Na
- Nitrogen - N
- Chlorine - Cl
- Hydrogen - H