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Andru [333]
3 years ago
12

The density of osmium, which is the densest metal, is 22.57g/cm3. What is the mass of a block of osmium that measures 1.00cm x 4

.00cm x 2.50cm? Show your work.
Please help and show work thank you.
Chemistry
2 answers:
Licemer1 [7]3 years ago
6 0

Answer:

225.70 grams is the mass of a block of osmium.

Explanation:

Density of the substance is defined as mass of the substance present in a unit volume of the substance.

Density=\frac{Mass}{Volume}

Density of the metal = \rho =22.57 g/cm^3

Mass of the block of an osmium metal = M

Volume of the block of an osmium metal = V

Block is in the shape of cuboid with dimension given as:

Length of the block = l = 1.0-0 cm

Breadth of the block = b = 4.00 cm

Height of the block = h = 2.50 cm

Volume of the block = V = l\times b\times h

\rho =\frac{M}{V}=\frac{M}{ l\times b\times h}

M = \rho\times  l\times b\times h

M=22.57 g/cm^3\times 1.00cm\times 4.00cm\times 2.50 cm

M = 225.70 g

225.70 grams is the mass of a block of osmium.

yanalaym [24]3 years ago
5 0
Hey there!:

Volume :

1.00 cm * 4.00 cm * 2.50 cm => 10 cm³

Density = 22.57 g/cm³

Therefore:

Mass = density * Volume

Mass = 22.57 * 10

Mass = 225.7 g
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Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

  • The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298}  = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

V_{2} = \frac{58752}{4023}\\\\

<h3>V₂ = 15 L </h3>

Therefore, the final volume of the gas is 15 L

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2 years ago
What characteristic frequencies in the infrared spectrum of your sodium borohydride reduction product will you look for to deter
kkurt [141]

Answer:

A)The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

B)Characteristic frequency  present in the infrared spectrum will be at a peak of  3300-3400 cm-1 which will be due to O-H stretch.

C)If the product is wet with water there will be no change in the infrared spectrum

Explanation:

The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

Characteristic frequency  present in the infrared spectrum will be at a peak of 3300-3400 cm-1 which will be due to O-H stretch.

If the product is wet with water there will be no change in the infrared spectrum

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Explanation:

Please see the step-by-step solution in the picture attached below.

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Answer: n=15.56moles

Explanation:

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