Answer:
See explanation
Explanation:
2HCl(aq) + CaCO3(aq) ------->CaCl2(aq) + CO2(g) + H2O(l)
Number of moles of acid present = 50/1000 * 0.15 = 0.0075 moles
Number of moles of calcium carbonate = 0.054g/100 g/mol = 0.00054 moles
2 moles of HCl reacts with 1 mole of calcium carbonate
x moles of HCl reacts with 0.00054 moles of calcium carbonate
x = 2 * 0.00054/1
x = 0.00108 moles of HCl
Amount of acid left = 0.0075 moles - 0.0075 moles = 0.00642 moles
Reaction of HCl and NaOH
HCl(aq) + NaOH(aq) ------> NaCl(aq) + H2O(l)
Since the reaction is in the mole ratio of 1:1
0.00642 moles of HCl is neutralized by 0.00642 moles of NaOH
Answer is: CH₃-CH₂-CH₂-NH₃⁺.
Amine group (-NH₂) has neutral charge, bet when accepts one proton (H⁺) has positive charge.
Amines<span> are </span>compounds<span> that contain a </span>basic nitrogen atom<span> with a </span>lone pair of electrons<span>. Amines are </span>derivatives<span> of </span>ammonia<span>, where is one or more </span>hydrogen<span> atoms replaced by a </span>substituent<span> such as an </span>alkyl<span> or </span>aryl<span> group (in this compound propyl group).</span>
The answer to ur question corresponds to the information u provided in option A.
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Answer:
Keq=0.866
Explanation:
Hello,
In this case, the undergone chemical reaction is:
In such a way, since 0.0055 mol of N₂O₄ remains in the flask, one infers that the reacted amount (
) was:
In addition, the produced amount of NO₂ is:
Finally, considering the flask's volume, the equilibrium constant is then computed as follows:
Best regards.
The equation is as follows:
Cyclohexane (C6H12) ⇔ Methyl cyclopentane (C6H12)
The equilibrium constant Kc = 0.143 >>> (1)
Qc is the reaction quotient
where; If Q = K >>>> No shift left or right >>> (2)
Q > K >>>> Reaction shifts left >>> (3)
Q < K >>>> Reaction shifts right >>> (4)
And in our equation; Q = 0.3 / 0.4 = 0.75 >>> (5)
From (1), (3) and (5), Q > Kc
∴ the reaction shifts left
