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3 years ago

How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg+2 ions?

Chemistry

1 answer:

Mnenie [13.5K]3 years ago

4 0

The number of moles of Cl- ions needed to combine completely with 0.25 mole of Mg+2 ions is:
0.50.

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Suppose that you add 26.7 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f Kf of 5.12 oC/m. With the a

kiruha [24]

From the calculation, the molar mass of the solution is 141 g/mol.

<h3>What is the molar mass?</h3>

We know that;

ΔT = K m i

K = the freezing constant

m = molality of the solution

i = the Van't Hoft factor

The molality of the solution is obtained from;

m = ΔT/K i

m = 3.89/5.12 * 1

m = 0.76 m

Now;

0.76 = 26.7 /MM/0.250

0.76 = 26.7 /0.250MM

0.76 * 0.250MM = 26.7

MM= 26.7/0.76 * 0.250

MM = 141 g/mol

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2 years ago

.The arrangement of constituent particles is most ordered in *

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Answer:

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Explanation:

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3 years ago

Consider the process in which HClO3 is converted to HClO2. The oxidation state of oxygen remains −2, and the oxidation state of

mixas84 [53]

Answer:

Option 1, Cl is reduced and gains electrons

Explanation:

HClO₃ → HClO₂

In HClO₃, chlorine acts with +5 in the oxidation state

In HClO₂,, chlorine acts with +3 in the oxidation state.

The state has been reducted, so the Cl has been reduced. As it was reduced, it means that has won e⁻, in this case 2

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2 years ago

Water vapor enters a compressor at 35 kpa and 160°c and leaves at 300 kpa with the same specific entropy as at the inlet. What a

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<h3>solution:</h3>

The initial entropy is obtained from the initial pressure and temperature with data from A-6 using interpolation:

s= 8.2652 kJ/kgK

The final temperature is determined from the entropy and the final pressure with data from A-6 using interpolation:

T₂ = T₁+ T₂ - T₁/ 8₂ - 8₁ ( s - s₁)

= (400 + 500 - 400/8.3271 - 8.0347 (8.2652 - 8))

= 478.83°C

The final enthalpy is determined in the same way:

h₂= h₁ + h₂ - h₁/s₂ - s₁ ( s - s₁)

= ( 3275.5+ 3486.6 - 3275.5/ 8.3271 - 8.0347) (8.265)

= 3441.91 kJ/kg

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2 years ago

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anzhelika [568]

Answer:

Al(No3)3

Explanation:

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2 years ago