Ideal Gas law PV=nRT
P- pressure(atm)
V-volume( liter)
R- gas constant
T- temperature(kelvin)
n - number of moles
Answer:
I think this answer should be 2.33 g H2O
Answer:
V₂ = 285 mL
Explanation:
Given data:
Initial volume of bag = 250 mL
Initial temperature = 19.0°C
Final temperature = 60.0°C
Final volume = ?
Solution:
The given problem will be solved by using Charles Law,
This law stated that " The volume of given amount of gas at constant pressure and constant number of moles is directly proportional to its temperature"
Mathematical relationship:
V₁/T₁ = V₂/T₂
Now we will convert the temperature into kelvin.
Initial temperature = 19.0 + 273 = 292K
Final temperature = 60.0 + 273 = 333K
Now we will put the values in formula:
V₁/T₁ = V₂/T₂
250 mL / 292K = V₂/ 333K
0.856 mL /K = V₂/ 333K
V₂ = 0.86×333K. mL /K
V₂ = 285 mL
Answer:
The answer to your question is Pressure 1 = 1.73 atm
Explanation:
Data
Volume 1 = 5 l
Pressure 1 = ?
Volume 2 = 12 l
Pressure 2 = 0.72 atm
Process
To solve this problem use Boyle's law to solve this problem
Pressure 1 x Volume 1 = Pressure 2 x Volume 2
-Solve for Pressure 1
Pressure 1 = Pressure 2 x Volume 2 / Volume 1
-Substitutiion
Pressure 1 = 0.72 x 12 / 5
-Simplification
Pressure 1 = 8.64/5
-Result
Pressure 1 = 1.73 atm
Someone added the answer already hope that helps you out