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Nadusha1986 [10]
3 years ago
9

Calculate the mass of

Chemistry
1 answer:
mixas84 [53]3 years ago
6 0

The mass of CO = 112 g

<h3>Further explanation </h3>

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³  particles

Moles can also be determined from the amount of substance mass and its molar mass

 

number of atoms in 88 g CO₂ :

\tt mass~O=\dfrac{2.16}{44}\times 88\\\\mol~O=\dfrac{mass~O}{Ar~O}=\dfrac{2.16.88}{44.16}=4\\\\number~of~atoms=4\times 6.02\times 10^{23}

number of atoms in CO :

\tt mass~O=\dfrac{16}{28}\times mass~CO

\tt mol~O=\dfrac{mass~O}{Ar~O}=\dfrac{16.mass~CO}{28.16}=\dfrac{mass~CO}{28}

\tt number~of~atoms=\dfrac{mass~CO}{28}\times 6.02\times 10^{23}

number of atoms in CO₂ = number of atoms in CO :

\tt 4\times 6.02\times 10^{23}=\dfrac{mass~CO}{28}\times 6.02\times 10^{23}\\\\4=\dfrac{mass~CO}{28}\\\\mass~CO=112~g

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3 years ago
In a recent study, 50 males used a new weight-loss supplement, and 37 of them experienced weight loss after two weeks: In the sa
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<em>Answer:</em>

The new weight-loss supplement was less effective on females in the study. That is because only 65% of them lost weight after two weeks, whereas 74% of the males lost weight after two weeks.

<em>Explanation:</em>

37 out of 50 males lost weight after two weeks, so 74% of males lost weight ( (37 · 2)/(50 · 2) ). 13 out of 20 females lost weight after two weeks, so 65% of females lost weight ( (13 · 5)/(20 · 5) ). This means the supplement was less effective on females because males had a higher percentage of losing weight.

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7 0
2 years ago
Five gases combined in a gas cylinder have the following partial pressures: 3. 00 atm (N2), 1. 80 atm (O2), 0. 29 atm (Ar), 0. 1
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The total pressure of the gaseous mixture has been 5.37 atm. Thus, option D is correct.

The partial pressure has been defined as the pressure exerted by each gas in the mixture.

According to the Dalton's law of partial pressure, the total pressure of gas has been the sum of the partial pressure of the gases in the mixture.

The given partial pressure of gases in the mixture has been:

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  • Partial pressure of Oxygen, P_O_2=1.80\;\rm atm
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The total pressure of the gaseous mixture has been:

P=P_N_2\;+\;P_O_2\;+\;P_A_R\;+\;P_H_e\;+\;P_H\\P=3\;+\;1.80\;+\;0.29\;+\;0.18\;+\;0.10\;\text {atm}\\P=5.37\;\rm atm

The total pressure of the gaseous mixture has been 5.37 atm. Thus, option D is correct.

For more information about partial pressure, refer to the link:

brainly.com/question/14623719

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2 years ago
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3 years ago
How many liters are in 20 grams of hydrogen gas?
motikmotik

\huge\bold{\mathfrak{\purple{A{\pink {n {\green {s{\blue{w{\red{e {\orange {r}}}}}}}}}}}}}

Volume of 20 g of hydrogen at normal temperature and pressure (NTP) = 240.55 ml.

\huge\sf\underline{\underline{\red{❥︎ Thanks}}}

3 0
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