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prisoha [69]
3 years ago
15

A factory at a low elevation ships bags of popcorn to cities at high elevations. Why does the factory manager need to monitor th

e amount of air in each bag
Chemistry
2 answers:
motikmotik3 years ago
8 0

Explanation:

Since factory is at low elevation, therefore, there will be more pressure. Similarly at high elevations there will be low pressure.

So, when bags of popcorn move from low elevation to high elevation the factory manager need to monitor the amount of air in each bag because if there are too many molecules in the bag then it will pop as it goes from high to low pressure areas.



german3 years ago
7 0

A factory at a low elevation ships bags of popcorn to cities at high elevations. The factory manager need to monitor the amount of air in each bag because when the bags of popcorn are delivered into high elevation cities, it will shrink due to the high pressure exerted by the surroundings towards the bag. As the elevation increases, the pressure surrounding it also increases.

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If 35.8 grams of LiCl are dissolved in 184 grams of water, what is the concentration of the solution in percent by mass?
True [87]
35.8/184=.194565, or 19.4565%
3 0
3 years ago
Read 2 more answers
The reaction described by H2(g)+I2(g)⟶2HI(g) has an experimentally determined rate law of rate=k[H2][I2] Some proposed mechanism
MatroZZZ [7]

Answer:

Mechanism A and B are consistent with observed rate law

Mechanism A is consistent with the observation of J. H. Sullivan

Explanation:

In a mechanism of a reaction, the rate is determinated by the slow step of the mechanism.

In the proposed mechanisms:

Mechanism A

(1) H2(g)+I2(g)→2HI(g)(one-step reaction)

Mechanism B

(1) I2(g)⇄2I(g)(fast, equilibrium)

(2) H2(g)+2I(g)→2HI(g) (slow)

Mechanism C

(1) I2(g) ⇄ 2I(g)(fast, equilibrium)

(2) I(g)+H2(g) ⇄ HI(g)+H(g) (slow)

(3) H(g)+I(g)→HI(g) (fast)

The rate laws are:

A: rate = k₁ [H2] [I2]

B: rate = k₂ [H2] [I]²

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]

<em>Where K' = K1 * K2</em>

C: rate = k₁ [H2] [I]

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]^1/2

Thus, just <em>mechanism A and B are consistent with observed rate law</em>

In the equilibrium of B, you can see the I-I bond is broken in a fast equilibrium (That means the rupture of the bond is not a determinating step in the reaction), but in mechanism A, the fast rupture of I-I bond could increase in a big way the rate of the reaction. Thus, just <em>mechanism A is consistent with the observation of J. H. Sullivan</em>

5 0
3 years ago
pls help!!! Calculate the pH of a solution with a H+ ion concentration of 2.6 x 10^-7 and round your answer to the nearest hundr
earnstyle [38]

Answer:

6.59

Explanation:

pH=-log[H+]

=-log[2.6×10^-7]

=6.59

8 0
3 years ago
B) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
snow_tiger [21]

Answer:

Explanation:

You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.

This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.

3 0
2 years ago
The element lanthanum has two stable isotopes, lanthanum-138 with an atomic mass of 137.9 AMU and lanthanum-139 with an atomic m
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Answer:

A. there is an isotope of lanthanum with an atomic mass of 138.9

Explanation:

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Now, the isotopes of an element are those elements, which have same number of electrons and protons as the original element, but different number of neutrons. Therefore, they have same atomic number but, different atomic weight or atomic masses.

Hence, by looking at an elements having same atomic number, but different atomic masses, we can identify them as isotopes.

Thus, the correct option is:

<u>A. there is an isotope of lanthanum with an atomic mass of 138.9.</u>

7 0
3 years ago
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