Can i just have the answers

Chemistry

1 answer:

JulijaS [17]4 years ago

3 0

https://www.teacherspayteachers.com/Product/Counting-Atoms-Worksheet-Editable-190185

id put em on here but i cant read them to good. Hope it helps tho!

fyi if u have other worksheets u need help on if u loo up the worksheet name and answer key itll prolly pop up.

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The movement of electrons causes:

ki77a [65]

Your answer is B ;) the movement of electrons cause electrical energy :)

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3 years ago

A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s

s344n2d4d5 [400]

We first calculate the heat released:
Specific heat = 3.21 kJ/kgK
Heat released = heat absorbed by calorimeter
Heat absorbed = mcΔT
= 1.9 x 3.21 x 4.542
= 27.7 kJ

Now, we calculate the moles of hexane present:
Moles = mass / Mr
moles = 0.58 / (12 x 6 + 14)
= 0.0067

Heat of combustion = 27.7 / 0.0067 kJ/mol

ΔH(combustion) = 4,134.3 kJ / mol

8 0

3 years ago

Read 2 more answers

Label the signals due to ha, hb, and hc in the 1h nmr spectra.

trapecia [35]

Structure along with ¹H-NMR is shown below.

Signal for Hₐ;
Based on multiplicity of of the peak, a Singlet peak (the only singlet peak present in spectrum) at 2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.

Signal for Hb;
Based on multiplicity of of the peak, a Quartet peak (the only quartet peak present in spectrum) at 2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.

Signal for Hc;
Based on multiplicity of of the peak, a Triplet peak (the only triplet peak present in spectrum) at 1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.

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4 years ago

Write and solve an equation

Nikitich [7]

all i know is that the formula for triangles is base times hight divided by two, so add in a number to replace the missing number, multiply it by 55 and divide the answer by two. hope this helps and i really hope you get it right! or that im right...

8 0

3 years ago

Methane at 10 mpa and 300 k is heated at constant pressure until its volume has increased by 80 percent. determine the final tem

katovenus [111]

When you assume that the gas is behaving ideally, the gas molecules are very far from each other that they do not have any intermolecular forces. If it behaves this way, you can assume the ideal gas equation:

PV = nRT, where

P is the pressure
V is the volume
n is the number of moles
R is a gas constant
T is the absolute temperature

When the process goes under constant pressure (and assuming same number of moles),

P/nR = T/V = constant, therefore,

T₁/V₁=T₂/V₂

If V₂ = V₁(1+0.8) = 1.8V₁, then,

T₂/T₁ = 1.8V₁/V₁

Cancelling V₁,

T₂/300=1.8
T₂ =540 K

If you do not assume ideal gas, you use the compressibility factor, z. The gas equation would now become

PV =znRT

However, we cannot solve this because we don't know the value of z₁ and z₂. There will be more unknowns than given so we won't be able to solve the problem. But definitely, the compressibility factor method is more accurate because it does not assume ideality.

7 0

3 years ago