Taking into account the Charles's law, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.
<h3>Charles's Law</h3>
Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, at a constant pressure.
Volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles's law is a law that says that the quotient that exists between the volume and the temperature will always have the same value:
V÷ T= k
Considering an initial state 1 and a final state 2, it is satisfied:
V1÷ T1= V2÷ T2
<h3>Volume at 65°C</h3>
In this case, you know:
- V1= 22.4 L
- T1= 0 C= 273 K
- V2= ?
- T2= 65 C= 338 K
Replacing in Charles's law:
22.4 L÷ 273 K= V2÷ 338 K
Solving:
(22.4 L÷ 273 K) ×338 K= V2
<u><em>V2= 27.73 L</em></u>
Finally, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.
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Answer: 1. rock stone gase from developing the other difference
Explanation:
If you have chipped or broken glassware then it is very important that you should take precaution yourself by conveying about it to your teacher and class mates.
By doing so you are making everybody aware to be cautious of the chipped or broken glassware.
Also, it is advised that you should dispose of it in the designated glass waste area.
Therefore, we can conclude that all actions that you should take if you have chipped or broken glassware as as follows.
- Dispose of it in the designated glass waste area.
Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is 
.
Explanation:
When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.
For example, chemical equation for oxidation of methane is as follows.
Number of atoms present on reactant side are as follows.
Number of atoms present on product side are as follows.
To balance this equation, multiply 
by 2 on reactant side. Also, multiply 
by 2 on product side. Hence, the equation can be rewritten as follows.
Now, the number of atoms present on reactant side are as follows.
Number of atoms present on product side are as follows.
Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.
Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is .
