An instrument that is used to measure air pressure is a ?

Given that a 12.00 g milk chocolate bar contains 8.000 g of sugar, calculate the percentage of sugar present in 12.00 g of milk

neonofarm [45]

So in order for us to know the percentage of sugar present in a 12.00 g of milk chocolate, what we are going to do is that, we just have to divide 8 by 12 and multiply in by 100 and we get 66.67. Therefore, the percentage of sugar present in 12.00 g of milk chocolate bar is 66.67%. Hope this answers your question. Have a great day!

5 0

3 years ago

Read 2 more answers

Potassium metal and chlorine gas combine in a reaction to produce an ionic compound. What is the correct balanced equation for t

Alisiya [41]

Answer:

2K (s) + Cl₂ (g) ⇒ 2KCl (s)

Explanation:

Potassium and chlorine gas combine to form potassium chloride which is an ionic compound. The reaction is a type of combination reaction in which chlorine is being added to the metal, potassium.

Potassium reacts violently with the chlorine which is yellowish green in color to produce white solid of potassium chloride.

The balanced reaction is shown below as:

2K (s) + Cl₂ (g) ⇒ 2KCl (s)

6 0

3 years ago

2C3H7OH + 9O2 --> 6CO2 + 8H2O

Ne4ueva [31]

<h3>Answer:</h3>

733 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O

[Given] 5.55 mol C₃H₇OH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol C₃H₇OH → 6 CO₂

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 5.55 \ mol \ C_3H_7OH(\frac{6 \ mol \ CO_2}{2 \ mol \ C_3H_7OH})(\frac{44.01 \ g \ CO_2}{1 \ mol \ CO_2})$
Multiply/Divide: $\displaystyle 732.767 \ g \ CO_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

732.767 g CO₂ ≈ 733 g CO₂

8 0

3 years ago

What are the Number of molecules of 14 grams of NO2

algol [13]

6.022 x 1023 atoms are in 14 grams of NO2

5 0

3 years ago

Find the number of moles of barium iodide if you have 5.23 x 1024 formula units of Bal2

Oksi-84 [34.3K]

Answer:

8.68 moles of BaI₂

Explanation:

Given data:

Number of moles of BaI₂ = ?

Number of formula units = 5.23× 10²⁴

Solution:

By using Avogadro number,

1 mole of any substance contain 6.022× 10²³ formula units.

5.23× 10²⁴ formula units of BaI₂ × 1 mol / 6.022× 10²³ formula units

0.868 × 10¹ moles of BaI₂

8.68 moles of BaI₂

Thus, 5.23× 10²⁴ formula units of BaI₂ contain 8.68 moles of BaI₂

7 0

3 years ago