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GREYUIT [131]
3 years ago
15

Find area PLEASE PLEASE PLEASE

Mathematics
2 answers:
UNO [17]3 years ago
3 0

Answer:

383.13

Step-by-step explanation:

Dima020 [189]3 years ago
3 0

Answer: 63.9 yd^2 (as in yards squared)

Step-by-step explanation:

1. Your formula is A=a+b/2*h, as in h times everything. a is your shorter base, b is your longer base, and h is the height.

2. Plug in the numbers. A=4.3+9.9/2*9.

3. A=14.2/2*9

4. A=7.1*9

5. A=63.9 yd^2

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What single transformation was applied to quadrilateral A to get quadrilateral B?<br> А<br> B
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Answer:

the answer is A

Step-by-step explanation:

8 0
3 years ago
If today is Tuesday, what day will it be three weeks from tomorrow?
worty [1.4K]
3 weeks from tomorrow will be Wednesday
3 0
3 years ago
Ayayayayauauauaua help
Cerrena [4.2K]

Answer:

I cant do them all for you, but essentially every equation there is an a, plug in 10 for a. Every equation  with b, plug in 9 and every equation with c plug in 4. Then Solve/simplify

Step-by-step explanation:

5 0
3 years ago
-13 times the difference between a number and 60 is equal to the number plus -59
kipiarov [429]
Let n represent the number.
  -13×(n -60) = n +(-59)
  -13n +780 = n -59
  839 = 14n
  839/14 = n = 59 13/14

The number is 59 13/14.

_____
Check
  The difference between the number and 60 is
    59 13/14 -60 = -1/14
  -13 times that value is
    -13*(-1/14) = 13/14
  Compare that to the number plus -59
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8 0
4 years ago
A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co
butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

8 0
4 years ago
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