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kodGreya [7K]
3 years ago
8

CarcuratOS 11.A credit card charges an annual rate of 18% compounded monthly. This month's bill is Rs. 35,000... Suppose that yo

u keep paying Rs. 5000 each month. How long will it take to pay off the bill? What is the total interest paid during that period? 111Over 10 years a bond costing Rs. 3000 increases in value to Rs. 5372.54. Find the effective annual rate.
Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

FIRST QUESTION

It will pay the bill after 7.45 = rounding 8 months, being the last payment less than 5,000

The total interest for the period will be 2,263.04

SECOND QUESTION The rate will be 6%

Step-by-step explanation:

for the first part, we should calculate the time it takes to an ordinary annuity of 5,000 to have a present value of 35,000 at discount rate of 18%

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 5,000

time n

rate 0.015

PV $35,000.0000

5000 \times \frac{1-(1+0.015)^{-n} }{0.015} = 35000\\

We work out the formula:

(1+0.015)^{-n}= 1-\frac{35000\times0.015}{5000}

We solve the right side of th formula

and then apply logarithmics properties:

-n= \frac{log0.895}{log(1+0.015)

-n = -7.450765527

n = 7.45

It will pay the bill after 8 months.

Total Interest: we will build the loan schedule:

         Bill          Interest    Cuota&Amortization

1      35000        525&      5000          4475

2     30525        457.88    5000         4542.12

3     25982.88  389.74     5000        4610.26

4     21372.62   320.59     5000         4679.41

5     16693.21   250.4       5000          4749.6

6     11943.61    179.15       5000          4820.85

7      7122.76    106.84     5000           4893.16

8       2229.6    33.44      2263.04       2229.6

Total              2263.04   37263.04       35000

The total interest for the period will be 2,263.04

<u>Second question </u>we will solve for the rate at which a capital of 3,000 returns 5,372.54 after 10 years

Principal \: (1+ r)^{time} = Amount

Principal 30,00.00

Amount = 5,372.54

time 10.00

rate ?

3,000 \: (1+ r)^{10} = 5,372.54

r = \sqrt[10]{5,372.54/3,000} - 1

r = 0.059999939 = 0.06 = 6%

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========================================================

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<u>Therefore, it can determined that :</u>

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