All categories

3 years ago

Is this how you work this out or am I doing it wrong

Mathematics

1 answer:

Sauron [17]3 years ago

8 0

You’re doing it right

You might be interested in

I neep help asap deadline 4:00pm

shutvik [7]

Answer: B each charm costs 15 dollars

Step-by-step explanation: because each money increment is 15$ so the answer is $15

~Brainliest would be appreciated

5 0

3 years ago

Convert the exponential function to the form indicated. (Round all coefficients to four significant digits.) f(x) = 2.5 e^(-0.7

Jobisdone [24]

$f(x)=2.5e^{-0.7x}=2.5\left(e^{-0.7}\right)^x\\\\A=2.5\\\\b=e^{-0.7}$

5 0

3 years ago

Please help me with this...

mr_godi [17]

I dont see anything u have to post on here whats the question you need help on ?

5 0

3 years ago

Read 2 more answers

Help i dont know the formula for the triangle to find the answer its surface area n volume

777dan777 [17]

Answer:

#4=10.5

#5=48

Step-by-step explanation:

The formula for the triangle for area is 1/2 time base times hight

The forumale fot the triangle for volume is 1/2 time base times hight

So for number #4 it will be 1/2 x 3 x 7

and number #5, it will be 1/2 x 8 x 12

5 0

2 years ago

A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker

valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is 3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

$V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}$

#Calculate amount of vinegar used in experiment:

$V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}$

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

$V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml$

Hence, the unused vinegar is 2100 ml

8 0

3 years ago

Is this how you work this out or am I doing it wrong​

Is this how you work this out or am I doing it wrong