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3 years ago

How many grams of KOH do we need to make 250.0ml of a 0.75 M

Chemistry

1 answer:

ZanzabumX [31]3 years ago

5 0

Answer:

10.52g KOH

Explanation:

250.0 ml X 1L/1000ml X 0.75 mol KOH/1L X 56.105gKOH/1 mol KOH =10.52g KOH

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Calculate the concentration of OH-in a solution that has a concentration of H+ = 8.1 x 10^−6 M at 25°C. Multiply the answer you

Nat2105 [25]

Answer:

The answer is 12.35

Explanation:

From the question we are given that the concentration of $H^{+}$ is $8.1 * 18^{-6}M$

Generally The rate equation is given as

$K_{w} = [H^{+} ][OH^{-} ]$

and $K_{w}$ the rate constant has a value $1 * 10^{-14}$

Substituting and making [ $OH^{-}$ ] the subject we have

$[OH^{-} ] = \frac{1 * 10^{-14}}{[H^{+}]} = \frac{1 * 10^{-14}}{8.1 *10^{-6}} =1.235 * 10^{-9}$

$[OH ^ {-}] = 1.235 * 10^{-9}M$

Multiply the value by $10^{10}$ as instructed from the question we have

Answer = $1.235 * 10 ^{-9} * 10^{10} = 12.35$

Hence the answer in 2 decimal places is 12.35

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3 years ago

A molecule with the formula ax4e uses _________ to form its bonds.

nadya68 [22]

Is it multiple choice?? Im thinking

A molecule with the formula ax4e uses sp3d to form its bonds.

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3 years ago

What is the temperature, in degrees Celsius, of a substance with a temperature of 49K? –322°C –224°C 224°C 322°C

vichka [17]

Answer:

-224ºC

Explanation:

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2 years ago

Key Concepts 4 Identify What are three advantages of using conceptual models? Help plz

liberstina [14]

Answer:

A Broad View of Concept Modeling

Establishing Key Relationships

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Explanation:

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3 years ago

When baking soda (sodium bicarbonate or sodium hydrogen carbonate, NaHCO3) is heated, it releases carbon dioxide gas, which is r

butalik [34]

Answer:

There is 78.25g NaHCO3 required

Explanation:

Step 1: Balance the equation

2 NaHCO3 → Na2CO3 + CO2 + H20

For 2 moles of NaHCO3 consumed, there is produced 1 mole of Na2CO3, 1 mole of CO2 and 1 mole of H2O.

Step 2: calculating moles of CO2

mass of Co2 = 20.5g

Molar mass of CO2 = 44.01 g/mole

moles of CO2 = 20.5 / 44.01 = 0.4658 moles

Step 3: Calculating moles of NaHCO3

Since we have for 1 mole CO2 produced, there is 2 moles of NaHCO3 consumed.

To calculate number of moles of NaHCO3, we have to multiply the number of moles of CO2, by 2.

⇒ 0.4658 x2 = 0.9316 moles

Step 4: Calculating the mass of NaHCO3

mass of NaHCO3 = moles of NaHCO3 x Molar mass of NaHCO3

mass = 0.9316 moles x 84g/ mole = 78.25g NaHCO3

There is 78.25g NaHCO3 required

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3 years ago