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3 years ago

a sample of water is mixed with a surfactant what will most likely happen to the viscosity of the water

2 answers:

5 0

The viscosity of water will decrease as it is directly related to intermolecular forces and when intermolecular forces decrease viscosity decreases.

aliya0001 [1]3 years ago

3 0

If a sample o water is mixed with a surfactant, the most likely result is that the viscosity of the water will increase. This is because of the property of the surfactant which is generally viscous; and becomes more viscous when mixed with water.

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Plz answer plzplzpzlpl

astraxan [27]

Whats the question tho?

8 0

2 years ago

This substance consists of two or more different elements chemically combined

kow [346]

The substance would be referred to as a compound substance.

8 0

2 years ago

The figure above shows the Earth at two different positions in its orbit around the Sun. Which position corresponds to summer in

Lelu [443]

Answer:

A. Position B.

Explanation:

In the summer the northern hemisphere is closer to the Sun so it's Position B.

3 0

3 years ago

Read 2 more answers

What does this equation, 2 C(s) + O 2(g) ® 2 CO(g), tell us?

Zanzabum

Answer:

D. All of these.

Explanation:

For an equation to be balanced the number of atoms of each kind in the reactants and the products should be the same.

Then from this equation, CO is a product.

Last, two carbon atoms undergo reaction with the oxygen molecule for complete reaction to occur. Each atom combines with one oxygen atom.

7 0

3 years ago

Read 2 more answers

At what temperature (°C) will a 10.00 g sample of neon gas exert a pressure of 96.7 kPa in a

Eva8 [605]

Answer : The temperature of neon gas will be, 221.0 K

Explanation :

To calculate the temperature of neon gas we are using ideal gas equation.

$PV=nRT\\\\PV=\frac{w}{M}RT$

where,

P = pressure of neon gas = 96.7 kPa = 0.955 atm

Conversion used : (1 atm = 101.3 kPa)

V = volume of neon gas = 9.50 L

T = temperature of neon gas = ?

R = gas constant = 0.0821 L.atm/mole.K

w = mass of neon gas = 10.00 g

M = molar mass of neon gas = 20 g/mole

Now put all the given values in the ideal gas equation, we get:

$(0.955atm)\times (9.50L)=\frac{10.00g}{20g/mole}\times (0.0821L.atm/mole.K)\times T$

$T=221.0K$

Therefore, the temperature of neon gas will be, 221.0 K

7 0

2 years ago