Answer: The right answer is 2
Step-by-step explanation:
- Write out the expression
T1; a = 0.3 ------------ (I)
T8; ar^7 = 38.4 ------------ (ii)
Substituting for 'a' in the second equation, we have;
0.3r^7 = 38.4
0.3r^7 = 38.4
Divide both sides by 0.3
r^7 = 38.4/0.3
r^7 = 128
r = (128)^1/7
r = 2
Here are the steps, also use photo math for fractions it explains and shows step by step. Also its free
2.625e14. now all u have ro do is simplify it
Each train carried 64141 kg of flour and each truck carried 9163 kg of flour.
Step-by-step explanation:
Let the no. of kg of flour carried by each train be 'a'
Let the no. of kg of flour carried by each truck be 'b'
Total flour = 403172 kg
No. Of trains = 5
No. of trucks = 9
a = 7(b)
5a + 9b = 403172
5(7b) + 9b = 403172
35b + 9b = 403172
44b = 403172
b = 403172/44
b = 9163
Each truck carried 9163 kg of flour.
a = 7b
a = 7(9163)
a = 64141
Each train carried 64141 kg of flour.
Given that <span>For
a certain model of car the distance

required to stop the vehicle if
it is traveling at

mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

Therefore, the range of speed she can travel is

</span>