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kozerog [31]
3 years ago
14

A fence is to be built to enclose a rectangular area of 220 square feet. The fence along three sides is to be made of material t

hat costs 3 dollars per foot, and the material for the fourth side costs 13 dollars per foot. Find the dimensions of the enclosure that is most economical to construct
Mathematics
1 answer:
VikaD [51]3 years ago
7 0

Answer: a rectangle is a quadrilateral having opposing sides parallel and four right angles

Area of rectangle = length * width

Step-by-step explanation: Given Area of rectangle = 220 square foot

1 side of the fence = 220/4 = 55 feet

If 3 sides of the fence cost $3

Total cost for 3 sides of the fence = ( 55 + 55 + 55) * 3 = 165 * 3 = $495

Total cos for the 4th side = 55 * 13 = $715

It is more economical to construct the fence with materials that cost $3.

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Help8b2 • 2b3 a) 16b-2 ,b) 16b6 ,c) 16b-4 ,d) 16b5
Travka [436]

Answer:

16b^5

Step-by-step explanation:

8b^2×2b^3

= 16b^2+3

= 16b^5

8 0
3 years ago
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Please help. Will give Brainliest.
san4es73 [151]

Answer:

x = 0

x = 7/5

x = -2/3

Step-by-step explanation:

x2 =0

x=0

5x -7 =0

5x = 7

x = 7/5

3x+2 =0

3x = -2

x = -2/3

These are all the 3 roots of this equation

3 0
2 years ago
Sam uses 2/3 cup of sugar to make cookies. How many cups will Sam use to make five batches. Write your answer in two ways. Impro
frosja888 [35]

Answer:

Improper fraction = 10/3 cups

Mixed fraction = 3 1/3 cups

Step-by-step explanation:

Given;

Sam uses 2/3 cup of sugar to make cookies

Rate = 2/3 cup per batch

To make 5 batches, he would need;

Amount = number of batches × rate per batch

Amount = 5 batches × 2/3 cups per batch

Amount of sugar he would need = 10/3 or 3 1/3 cups

4 0
2 years ago
Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).
spayn [35]

The Bernoulli distribution is a distribution whose random variable can  only take 0 or 1

  • The value of E(x2) is p
  • The value of V(x) is p(1 - p)
  • The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * (1- p) + 1^2 * p

Evaluate the exponents

E(x^2) = 0 * (1- p) + 1 * p

Multiply

E(x^2) = 0 +p

Add

E(x^2) = p

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

V(x) = E(x^2) - (E(x))^2

Start by calculating E(x) using:

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * (1- p) + 1 * p

E(x) = p

Recall that:

V(x) = E(x^2) - (E(x))^2

So, we have:

V(x) = p - p^2

Factor out p

V(x) = p(1 - p)

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

E(x^{79}) = \sum x^{79} * P(x)

So, we have:

E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p

Evaluate the exponents

E(x^{79}) = 0 * (1- p) + 1 * p

Multiply

E(x^{79}) = 0 + p

Add

E(x^{79}) = p

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

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2 years ago
What is the value of in e4
arlik [135]

4 is your answer yw luv

8 0
3 years ago
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