Question

Un acróbata de 60 kg realiza un acto de equilibrio sobre un bastón. El extremo del bastón, en contacto con el piso, tiene un área de 0.92 cm2. Calcule la presión que el bastón ejerce sobre el piso (desprecie el peso del bastón).

Answer 1

Answer:

Pressure, $P=6.39\times 10^6\ Pa$

Explanation:

A 60 kg acrobat performs a balancing act on a cane. The end of the cane, in contact with the floor, has an area of ​​0.92 cm2. Calculate the pressure the cane exerts on the floor (neglect the weight of the cane).

We have,

Mass of acrobat, m = 60 kg

The end of the cane, in contact with the floor, has an area of, $A=0.92\ cm^2=0.92\times 10^{-4}\ m^2$

It is required to find the the pressure the cane exerts on the floor. Pressure exerted by an object is defined as the force acting per unit its area. Its formula is written as :

$P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{60\times 9.8}{0.92\times 10^{-4}}\\\\P=6.39\times 10^6\ Pa$

So, the pressure the cane exerts on the floor is $6.39\times 10^6\ Pa$.