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Elan Coil [88]
3 years ago
5

1. True or False: Most things in motion are accelerating, few things in real life move at a constant speed.

Physics
1 answer:
lord [1]3 years ago
5 0
1. False
2. Positive
I’m just joking I don’t know the answersss
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A 675 kg car moving at 15.7 m/s hits from behind another car moving at 9.6 m/s in the same direction. If the second car has a ma
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3 years ago
Which of The following is the best example of water changing from a liquid to gas
expeople1 [14]

Answer:

There are no examples but this should be evaporation

Explanation:

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3 years ago
What does an electromagnet have that a bar magnet does not ?
Anon25 [30]
The bar magnet and the electromagnet act identical. The difference being a electromagnet is a coil of wire that has a power source connect to both ends, this energizes the coil with an electromagnetic field.
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3 years ago
A rock is being twirled in a circle on the end of a string. The string provides the centripetal force needed to keep the ball mo
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Answer:

No

Explanation:

The force of tension exerted by the string on the rock acts as centripetal force, so its direction is always towards the centre of the circle.

However, the direction of motion of the rock is always tangential to the circle: this means that the force is always perpendicular to the direction of motion of the rock.

As we know, the work done by a force on an object is

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the force and the displacement

In this situation, F and d are perpendicular, so \theta=90^{\circ}, therefore cos \theta = 0 and the work done is zero:

W=0

4 0
2 years ago
What is the total energy of a particle with a rest mass of 1 gram moving with half the speed of light? 1 eV = 1.6 x 10^-19 J. An
GREYUIT [131]

Answer:

6.5 x 10^32 eV

Explanation:

mass of particle, mo = 1 g = 0.001 kg

velocity of particle, v = half of velocity of light = c / 2

c = 3 x 10^8 m/s

Energy associated to the particle

E = γ mo c^2

E=\frac{m_{0}c^}2}{\sqrt{1-\frac{v^{2}}{c^{2}}}}

E=\frac{m_{0}c^}2}{\sqrt{1-\frac{c^{2}}{4c^{2}}}}

E=\frac{2m_{0}c^}2}{\sqrt{3}}

E=\frac{2\times0.001\times9\times10^{16}}{1.732}

E=1.04\times10^{14}J

Convert Joule into eV

1 eV = 1.6 x 10^-19 J

So, E=\frac{1.04\times10^{14}}{1.6\times10^{-19}}=6.5\times10^{32}eV

4 0
2 years ago
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