Refer to the diagram shown below.
Let the truck be traveling north at 20 m/s.
Let the ball be shot eastward at 20 m/s
The resultant velocity of the ball is
v = √(20² + 20²) = 20√2 = 28.284 m/s
The direction is
θ = tan⁻¹ (20/20) = tan⁻¹ 1 = 45°
Answer:
The ball travels at 28.3 m/s at 45° relative to the direction of the truck.
Answer:
Volume flow rate 
meter cube per second
Explanation:
As we know that the
Pressure at the two ends would be the same along with volume of flow.
i.e
and
Re arranging the file, we get -
The flow equation is
Substituting the value of 
in above equation, we get -
Substituting the given values in above equation we get
Volume flow rate
we know that momentum is given as
P = mv
where P = momentum , m = mass , v = velocity
taking derivative both side relative to "t"
dP/dt = v (dm/dt)
we know that : dP/dt = F = force
hence
F = v (dm/dt)
given that :
dm/dt = rate of mass expelled = 1500 kg/s
v = velocity = 4 x 10⁴ m/s
hence , inserting the values in the above formula
F = (4 x 10⁴) (1500)
F = 6 x 10⁷ N
Answer:
The mass of the objects
Distance between the objects
Explanation:
The two factors that determines the amount of gravitational force between two objects is the mass of the objects and the distance between them.
Gravitational force of attraction is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance between them. This is the postulate of the newton's law of universal gravitation.
Mathematically:
F = 
m is the mass
r is the distance
G is the universal gravitation constant
Given that,
bug speed, v= 0.85 m/s
time, t =42 s
Final position of bug on meter stick was 27 cm
Starting position of bug on meter stick = ?
Since we know that,
s = vt
s= 0.85*42 = 35.7 cm
this is the distance covered by bug in the given time and velocity.
since the bug is moving in negative direction, starting point will be:
27.0 cm+ 35.7 cm = 62.7 cm
The bugs starting position on meter stick was 62.7 cm.
