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lesantik [10]
3 years ago
11

What is the difference between accurate data and reproducible data?

Physics
2 answers:
Shtirlitz [24]3 years ago
5 0

Answer:


Accuracy is ‘the state of being correct’ and on the other hand precision is ‘the state of being exact.


Explanation:


Accuracy shows the nearness of the measurement with the actual measurement while precision shows the nearness of an individual measurement with other measurements.


Accuracy focuses on the errors caused by the problem in the instrument. while precision is concerned with errors, which occurs periodically with no recognizable pattern.


If the measurement is precise but inaccurate, the result will not be the expected one. And if the result is accurate but imprecise, then there are huge variations in the measurements. And finally, if the actual measurement is neither accurate nor precise, then the result would not have correctness and exactness at the same time.

vladimir1956 [14]3 years ago
4 0
Accuracy is a general concept while precision is more of a mathematical concept.
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CO + 7H2 - C3Hg + 3H20
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Answer:

Espanol 7h2 that's c coupon

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2 years ago
Which list accurately identifies the hierarchy of space from largest to smallest? Solar system, galaxy, planet, universe Galaxy,
Oliga [24]
<h3><u>Answer;</u></h3>

Universe, galaxy, solar system, planet, moon

<h3><u>Explanation;</u></h3>
  • <u>A galaxy</u>, such as our Milky Way Galaxy, is a collection of solar systems orbiting around a central core.
  • <u>A solar system</u> consists of a star, normally the sun and all of its planets, asteroids, comets and other bodies.
  • <u>A planet</u> is a nearly spherical body which is in orbit around the Sun. Planets are larger than moons.
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8 0
3 years ago
Read 2 more answers
Helicopters rotor blades, could spin at high speed of 510 rpm. Find the angular displacement in radian for 3 hour(s) operation
malfutka [58]

Answer:

The angular displacement of the blade is 576,871.2 radians

Explanation:

Given;

angular speed of the Helicopters rotor blades, ω = 510 rpm (revolution per minute)

time of motion, t = 3 hours

The angular speed of the Helicopters rotor blades in radian per second is given as;

\omega = \frac{510 \ rev}{mins} *\frac{2 \pi \ rad}{1 \ rev} *\frac{1 \ min}{60 \ s}\\\\\omega =  53.414 \ rad/s

The angular displacement in radian is given as;

θ = ωt

where;

t is time in seconds

θ = (53.414)(3 x 60 x 60)\\

θ = 576,871.2 radians

Therefore, the angular displacement of the blade is 576,871.2 radians

5 0
3 years ago
With what minimum speed must you toss a 200 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release
Brut [27]
When they say use energy, you want to use

Total energy = potential energy + kinetic energy = mgh + 1/2mv²

I assume you mean 200 g ball,

so, we know the total distance traveled is going to be 13 - 1.3 = 11.7 m

If the ball just makes it to the top ( 13 m ) , then the ball will stop moving and the kinetic energy will be 0,

therefore, the potential energy at the top will be the total energy of the system = mgh

from this, we say that mgh = 1/2mv² solve for v

<span> v = sqrt (2gh) = 15.2 m/s </span>
8 0
3 years ago
The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by
Eduardwww [97]

Complete Question:

A 10 kg block is pulled across a horizontal surface by a rope that is oriented at 60° relative to the horizontal surface.

The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by the tension in the rope if the block when the block is 5 m away from its starting point? The coefficient of kinetic friction between the block and the floor is 0.2 and you may assume that the block starting at rest.

Answer:

Power = 54.07 W

Explanation:

Mass of the block = 10 kg

Angle made with the horizontal, θ = 60°

Distance covered, d = 5 m

Tension in the rope, T = 40 N

Coefficient of kinetic friction, \mu = 0.2

Let the Normal reaction = N

The weight of the block acting downwards = mg

The vertical resolution of the 40 N force, f_{y} = 40sin \theta

\sum f(y) = 0

N + 40 sin \theta - mg = 0\\N = -40sin60 + 10*9.81 = 0\\N = 63.46 N

\sum f(x) = 0

40 cos 60 - f_{r} - ma = 0\\ f_{r} = \mu N\\ f_{r} = 0.2 * 63.46\\ f_{r} = 12.69 N\\40cos 60 - 12.69-10a = 0\\7.31 = 10a\\a = 0.731 m/s^{2}

v^{2}  = u^{2} + 2as\\u = 0 m/s\\v^{2}  =  2 * 0.731 * 5\\v^{2}  = 7.31\\v = \sqrt{7.31} \\v = 2.704 m/s

Power, P = Fvcos \theta

P = 40 *2.704 cos60\\P = 54.074 W

7 0
3 years ago
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